3 years ago

1. what is the height of a cone whose radius is 3 cm and volume is 900 cm3?

1 answer:

7 0

R = 3cm
V = 900 cm^3

V = pi * r^2 * h / 3
900 = (22/7) * 3^2 * h/3
h = (900*3*7) / 22 / 3^2
h = 18900 / 22 / 9
h = 95.45 cm

You might be interested in

Eddi Din [679]

After factoring $3x^3-27x=0$ the solutions are x=0 , x=3, x= -3

Step-by-step explanation:

We need to solve by factoring:

$3x^3-27x=0$

Solving:

$3x^3-27x=0$

Taking 3x common:

$3x(x^2-9)=0$

Now using formula $a^2-b^2=(a-b)(a+b)$

$3x((x)^2-(3)^2)=0\\3x(x-3)(x+3)=0$

$3x=0\,\,and\,\,x+3=0\,\,and\,\,x-3=0\\x=0\,\,and\,\,x=-3\,\,and\,\,x=3\\$

So, After factoring $3x^3-27x=0$ the solutions are x=0 , x=3, x= -3

Keywords: Factorization

Learn more about Factorization at:

#learnwithBrainly

5 0

3 years ago

Neporo4naja [7]

The second one is the only equivalent equation. Simply plug in each variable in each equation. And compare!

4 0

3 years ago

babymother [125]

Rebekah's baby weighs 7.47 more than her kitten

4 0

3 years ago

zysi [14]

C - (x-3)^2=36

If we expand (x-3)^2=36:

(x-3)(x-3)=36
x^2-3x-3x+9=36
x^2-6x+9=36

Then subtract 36

x^2-6x-27=0

7 0

3 years ago

andrey2020 [161]

Answer:

i am gessing to divide

Step-by-step explanation:

3 0

3 years ago