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Debora [2.8K]
3 years ago
12

How many ways can you make a 5-letter passcode using the digits a,b,c,d,e,f,g,h,i,j if repetition of letters is not allowed?

Mathematics
1 answer:
timama [110]3 years ago
5 0
You can use the letters: a, b, c, d, e, f, g , h, i, and j to make a 5-letter passcode. So you have 10 letters.
For the 1st place you can use 10 letters, for the 2nd you can use 9 ( because the repetition of letters is not allowed ) and so on.
Therefore: 10 * 9 * 8 * 7 * 6 = 30,240
It is also known as a variation of m elements choose n ( V m,n ):
V (10, 5 ) = m * ( m - 1 ) *...* ( m - n + 1 ) = 10 * 9 * 8 * 7 * 6 = 30,240
Answer: You can make a passcode in 30,240 ways.
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Assume adults have IQ scores that are normally distributed with a mean of 102 and standard deviation of 16. Find the probability
Andre45 [30]

Answer:

57.49% probability that a randomly selected individual has an IQ between 81 and 109

Step-by-step explanation:

When the distribution is normal, we use the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this question, we have that:

\mu = 102, \sigma = 16

Find the probability that a randomly selected individual has an IQ between 81 and 109

This is the pvalue of Z when X = 109 subtracted by the pvalue of Z when X = 81. So

X = 109

Z = \frac{X - \mu}{\sigma}

Z = \frac{109 - 102}{16}

Z = 0.44

Z = 0.44 has a pvalue of 0.67

X = 81

Z = \frac{X - \mu}{\sigma}

Z = \frac{81 - 102}{16}

Z = -1.31

Z = -1.31 has a pvalue of 0.0951

0.67 - 0.0951 = 0.5749

57.49% probability that a randomly selected individual has an IQ between 81 and 109

8 0
3 years ago
Can you please answer the question?
Sliva [168]

Answer:

I think its 21 im not sure tho! Sorry if im wrong! :(

Step-by-step explanation:

6 0
3 years ago
Meryl needs to cut down 10.5 trees for every 555 cabins she builds.
inysia [295]

<u>Answer: </u>

6.3 trees.

<u>Step-by-step explanation: </u>

We have been given that Meryl needs to cut down 10.5 trees for every 5 cabins she builds.

Let us find the number of trees Meryl needs to cut down to build 1 cabin by dividing 10.5 by 5.

Now let us multiply 2.1 by 3 to find the number of trees Meryl needs to cut down to build 3 cabins.

Therefore, Meryl needs to cut down 6.3 trees, if she builds 3 cabins.

4 0
3 years ago
Please help me find the same denominator
Lelechka [254]

Answer:

\huge\underline{\red{A}\blue{n}\pink{s}\purple{w}\orange{e}\green{r} -}

let us first start with some basic information ~

A fraction can be represented as \frac{x}{y}\\ where ,

x is the numerator and y is the denominator !

the question asks us to do something that will help us get same denominator for both the terms !

so let's see what we should do in such a case ~

\frac{9}{10}  \: and \:  \frac{7}{8}  \\ \\ \\ lets \: make \: the \: denominator \: of \: both \\ the \: terms \: reach \: 80 \: , \\  \\ \bold\orange{ \implies \: \frac{9}{10}  \times  \frac{8}{8}  = }\bold\red{ \frac{72}{80}}  \\  \\\bold\orange{ \implies \:  \frac{7}{8}  \times  \frac{10}{10}  =}\bold\red{  \frac{70}{80}}

and we're done !

let's add some more info to be lil more clear ~

while converting the denominator of both the terms , we must multiply the same number ( this number refers to the one we'll have to multiply to the denominator to obtain the desired result ) with the denominator as well as with the numerator !

hope helpful :D

6 0
2 years ago
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A pool has an area of 1,275 m2 and a width of 25 1 2 m. What is the length of the pool?
Anarel [89]
Is it meant to be 251m^2?
 and what are your choices
7 0
3 years ago
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