All categories

3 years ago

21 times a number increased

Mathematics

2 answers:

IRINA_888 [86]3 years ago

8 0

Answer:

Step-by-step explanation:

21x + 6 = 3x + 60 subtract 3x from both sides

(21x-3x) + 6 = 60

18x + 6 = 60 subtract 6 from both sides

18x= 60-6

18x= 54 divide by 18

x =3

Leokris [45]3 years ago

6 0

Answer: the number is 3

Step-by-step explanation:

This can be written mathematically as

21y + 6 = 60 + 3y

21y - 3y = 60 - 6

18y = 54

y = 54/18 = 3

You might be interested in

Which statement correctly describes the relationship between the graph of f(x)= x and the graph of g(x) = f (x-10)

NemiM [27]

I think it’s C
I am not sure though

4 0

3 years ago

An integer between 4.5 and 5.5

Brums [2.3K]

Answer: 5

Step-by-step explanation:

the only whole number between them is 5 <3

3 0

3 years ago

2. It costs Edgar $2.65 one way to ride the bus to work. He uses the bus to go to and from work four days per week. He buys a bo

Maurinko [17]

$27

2.65 x 2 (since he has to go both to and from work each day) = $5.30
Add the daily cost of the water bottle (1.45) to make his total cost for one day, which is 6.75
Multiply this number by 4 (because he goes 4 days a week) to get $27 for one week.

6 0

3 years ago

(x +y)^5<br> Complete the polynomial operation

Vesna [10]

Answer:

Please check the explanation!

Step-by-step explanation:

Given the polynomial

$\left(x+y\right)^5$

$\mathrm{Apply\:binomial\:theorem}:\quad \left(a+b\right)^n=\sum _{i=0}^n\binom{n}{i}a^{\left(n-i\right)}b^i$

$a=x,\:\:b=y$

$=\sum _{i=0}^5\binom{5}{i}x^{\left(5-i\right)}y^i$

so expanding summation

$=\frac{5!}{0!\left(5-0\right)!}x^5y^0+\frac{5!}{1!\left(5-1\right)!}x^4y^1+\frac{5!}{2!\left(5-2\right)!}x^3y^2+\frac{5!}{3!\left(5-3\right)!}x^2y^3+\frac{5!}{4!\left(5-4\right)!}x^1y^4+\frac{5!}{5!\left(5-5\right)!}x^0y^5$