Answer:
3x+13
Step-by-step explanation:
squares have 4 equal sides
12/4=3x
52/4=13
3x+13
is that 3rd option supposed to be what i put???
hope this helped
plz mark Brainliest so i can rank up!
Answer:
<h2>35 different ways</h2>
Step-by-step explanation:
Since there are 7 students in a classroom to fill a front row containing 3 seats, we will apply the combination rule since we are to select 3 students from the total number of 7 students in the class.
In combination,<em> if r objects are to be selected from a pool of n objects, this can be done in nCr number of ways.</em>
<em>nCr = n!/(n-r!)r!</em>
Selecting 3 students from 7 students to fill the seats can therefore be done in 7C3 number of ways.
7C3 = 7!/(7-3)!3!
7C3 = 7!/(4)!3!
7C3 = 7*6*5*4!/4!*3*2
7C3 = 7*6*5/6
7C3 = 7*5
7C3 = 35
<em>Hence there are 35 different ways that the student can sit in the front assuming there are no empty seats.</em>
Answer:
Option (1) ; y = 7x
Step-by-step explanation:
(1) reads y = 7x, a line with slope 7, therefore the rate of change in this is 7
(2) says that y increases 12 units every time that x increases 4 Then the rate of change is: (increase in y / increase in x = 12/4 =3
(3) shows a table from which we can see that an increase of y in 8 corresponds to an increase of x in 2: rate of change = (8 - 0) , (2 - 0) = 4
(4) shos a line with slope (rate of change) given by: (12 - 0) / (2 - 0) = 12/2 = 6
Therefore, the greatest rate of change is shown by the first expression
y = 7 x
3(x^2+10x+5)-5(x-k)=
3x^2+30x+15-5x+5k=
3x^2+25x+15+5k
for this to be divisible by x every term must include x or get eliminated
the problematic terms are 15 and 5k
to eliminate them they must equal 0 when added:
15+5k=0
5k=-15
k=-3
so A) -3 is the solution
