Nine subtracted from twice a niumber
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<span>Given:
AB = x + 16
BC = 4x + 11
AC= 77
We can safely assume that,
AB + BC = AC
x + 16 + 4x + 11 = 77
5x + 27 = 77
5x = 77 - 27
5x = 50
x = </span>
x = 10
Hence,
AB = x + 16 = 10 + 16 = 26
Hence, proved.
AB = x + 16
BC = 4x + 11
AC= 77
We can safely assume that,
AB + BC = AC
x + 16 + 4x + 11 = 77
5x + 27 = 77
5x = 77 - 27
5x = 50
x = </span>
x = 10
Hence,
AB = x + 16 = 10 + 16 = 26
Hence, proved.
