Answer:
Distance= 6.6 miles
Bearing= N 62.854°W
Step-by-step explanation:
Let's determine angle b first
Angle b=20° (alternate angles)
Using cosine rule
Let the distance between the liner and the port be x
X² =8.8²+2.4²-2(8.8)(2.4)cos20
X²= 77.44 + 5.76-(39.69)
X²= 43.51
X= √43.51
X= 6.596
X= 6.6 miles
Let's determine the angles within the triangle using sine rule
2.4/sin b = 6.6/sin20
(2.4*sin20)/6.6= sin b
0.1244 = sin b
7.146= b°
Angle c= 180-20-7.146
Angle c= 152.854°
For the bearing
110+7.146= 117.146
180-117.146= 62.854°
Bearing= N 62.854°W
Answer:
f(x) = (x + 2) (x − 5) (x − 6)
Step-by-step explanation:
f(x) = (x − (-2)) (x − 5) (x − 6)
f(x) = (x + 2) (x − 5) (x − 6)
The equation for slope is y=mx+b. slope is m. 2 is the slope. so you know the m part of the equation is 2. just by eliminating the answers that don’t have 2 as the slope, A is your answer.
1) 5.1
2)7.9
3) 4
4)20
5)8.9
6) 4.2
7)5.2
8)15
I'am somewhat confident that some are right because iam not sure your suppose to round the nearst tenth
i dont know srry
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