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Naya [18.7K]
3 years ago
12

If both coordinates of a point are positive, in which quadrant is that point located?

Mathematics
2 answers:
BabaBlast [244]3 years ago
7 0

Answer:

A

Step-by-step explanation:

Both points are positive in the 1st quadrant.

Ilia_Sergeevich [38]3 years ago
6 0

Answer:

A. l

Step-by-step explanation:

Both coordinates are in quadrant 1 because both x and y in quadrant 1 must be positive.

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What is the volume of a sphere with a diameter of 9.3 m, rounded to the nearest
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Answer:

Step-by-step explanation:

about 17

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(ASAP) Billie & Tony are siblings. It’s summer of 2015. Twice Billie’s age decreased by 3 is Tony’s age. Tony is fourteen ye
jeka94

Answer:

Billie's age = x = 17 years

Tony's age = y = 31 years

Step-by-step explanation:

Let

Billie's age = x

Tony's age = y

Twice Billie’s age decreased by 3 is Tony’s age.

y = 2x - 3..... Equation 1

Tony is fourteen years older than Billie.

x = y - 14

We substitute y - 14 for x in Equation 1

y = 2x - 3..... Equation 1

y = 2(y - 14) - 3

y = 2y - 28 - 3

y - 2y = -28 - 3

-y = -31

y = 31 years

Solving for x

x = y - 14

x = 31 - 14

x = 17 years.

Therefore:

Billie's age = x = 17 years

Tony's age = y = 31 years

4 0
3 years ago
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A new grocery store is expected to have a fair market value of $2,856,000. It will be assessed at 40%, and the tax rate is $5.24
olganol [36]
Assessed Value = (Fair Market Value) x (0.40) Where 0.40 is the decimal equivalent of 40%. Tax Rate = $5.24/$100 of assessed value = $0.0524 per dollar of assessed value. Taxes = (Assessed Value) x (Tax Rate) = (Assessed Value) x ($0.0524) Hope this helps!
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Finding Derivatives Implicity In Exercise, find dy/dx implicity.<br> x2 - 3 ln y + y2 = 10
Veseljchak [2.6K]

Answer:

\frac{dy}{dx}=-\frac{2xy}{2y^2-3}

Step-by-step explanation:

We are given that

x^2-3lny+y^2=0

Differentiate w.r.t x

2x-\frac{3}{y}\frac{dy}{dx}+2y\frac{dy}{dx}=0

By using formula

\frac{dx^n}{dx}=nx^{n-1}

\frac{d(lnx)}{dx}=\frac{1}{x}

\frac{dy^n}{dx}=ny^{n-1}\frac{dy}{dx}

\frac{dy}{dx}(-\frac{3}{y}+2y)+2x=0

\frac{dy}{dx}(-\frac{3}{y}+2y)=-2x

\frac{dy}{dx}=-\frac{2x}{-\frac{3}{y}+2y}

\frac{dy}{dx}=-\frac{2xy}{2y^2-3}

Hence, the derivative of function

\frac{dy}{dx}=-\frac{2xy}{2y^2-3}

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