If both coordinates of a point are positive, in which quadrant is that point located?
2 answers:
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Answer:
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Step-by-step explanation:
For all real numbers a,b, and c, the distributive property states that:
For Part A, we have
Or
For Part B, we have
-4(3x-10)+5(2-6x)=-4*3x--4*10+5*2-5*6x
This simplifies to:
-4(3x-10)+5(2-6x)=-12x+40+10-30x
-4(3x-10)+5(2-6x)=-12x-30x+40+10
-4(3x-10)+5(2-6x)=-42x+50
For the C part, we have:
For Part D, we have:
We simplify to get:
Simplify further to get:
The exact measure of the angle is 45°.
<h3>How to get the angle?</h3>
We know that the terminal side passes through a point of the form (√2/2, y).
Notice that the point is on the unit circle, so its module must be equal to 1, so we can write:
We know that y is positive because the point is on the first quadrant.
Now, we know that our point is:
(√2/2, 1/√2)
And we can rewrite:
√2/2 = 1/√2
So the point is:
( 1/√2, 1/√2)
Finally, remember that a point (x, y), the angle that represents it is given by:
θ = Atan(y/x).
Then in this case, we have:
θ = Atan(1/√2/1/√2) = Atan(1) = 45°
If you want to learn more about angles, you can read: