Which decimal number is represented?

What is the simplified expression for 3 y squared minus 6 y z minus 7 + 4 y squared minus 4 y z + 2 minus y squared z? y squared

tresset_1 [31]

Answer:

7y^2 - y^2z - 10yz-5

C. 7 y squared minus y squared z minus 10 y z minus 5

Step-by-step explanation:

A. y squared minus y squared z minus 10 y z minus 5

B. y squared minus y squared z minus 5 y z minus 5

C. 7 y squared minus y squared z minus 10 y z minus 5

D. 7 y squared minus y squared z minus 2 y z minus 5

Given:

3y^2 - 6yz - 7 + 4y^2 - 4yz + 2 - y^2z

Collect like terms in the expression

3y^2 + 4y^2 - 6yz - 4yz - y^2z - 7 + 2

Simplify

7y^2 - 10yz - y^2z - 5

Rewritten as

7y^2 - y^2z - 10yz-5

Option C. 7 y squared minus y squared z minus 10 y z minus 5

Is the answer

4 0

4 years ago

Write 7 22/55 as a decimal. PLS HELP I HAVE 3 MINUTES LEFT!!!

EastWind [94]

7.45 I think it 7.46

3 0

3 years ago

Lena has 2 boxes of buttons A and B.In total are 1.200 buttons .She move 360 buttons from box A to B.There are now 3 times as ma

Fittoniya [83]

Answer:

660

Step-by-step explanation:

Let A = number of buttons in Box A

and B = number of buttons in Box B

We have two conditions:

(1) A + B = 1200

(2) B + 360 = 3(A – 360) Remove parentheses

B + 360 = 3A - 1080 Subtract 360 from each side

(3) B = 3A - 1440 Substitute (3) into (1)

A + 3A - 1440 = 1200 Combine like terms

4A - 1440 = 1200 Add 1440 to each side

4A = 2640 Divide each side by 4

A = 660

6 0

3 years ago

2 1/2 - 4 1/4 any one know what this answer is please help

MaRussiya [10]

Answer:

=5/2 - 17/4

=10/4 - 17/4

= -7/4

........................

7 0

3 years ago

In a survey of 1000 women age 22 to 35 who work full time, 540 indicated that they would be willing to give up some personal tim

hram777 [196]

Answer:

$z=\frac{0.540-0.5}{\sqrt{\frac{0.5(1-0.5)}{1000}}}=2.53$

$p_v =P(Z>2.53)=0.0057$

So the p value obtained was a very low value and using the significance level given $\alpha=0.01$ we have $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 1% of significance the true proportion is not significantly higher than 0.5.

Step-by-step explanation:

1) Data given and notation

n=1000 represent the random sample taken

X=540 represent the people indicated that they would be willing to give up some personal time in order to make more money

$\hat p=\frac{540}{1000}=0.54$ estimated proportion of people indicated that they would be willing to give up some personal time in order to make more money

$p_o=0.5$ is the value that we want to test

$\alpha=0.01$ represent the significance level

Confidence=99% or 0.99

z would represent the statistic (variable of interest)

$p_v$ represent the p value (variable of interest)

2) Concepts and formulas to use

We need to conduct a hypothesis in order to test the claim that the majority of women age 22 to 35 who work full-time would be willing to give up some personal time for more money :

Null hypothesis: $p\leq 0.5$

Alternative hypothesis: $p > 0.5$

When we conduct a proportion test we need to use the z statistic, and the is given by:

$z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}}$ (1)

The One-Sample Proportion Test is used to assess whether a population proportion $\hat p$ is significantly different from a hypothesized value $p_o$ .

Check for the assumptions that he sample must satisfy in order to apply the test

a)The random sample needs to be representative: On this case the problem no mention about it but we can assume it.

b) The sample needs to be large enough

$np_o =100*0.5=500>10$

$n(1-p_o)=1000*(1-0.5)=500>10$

3) Calculate the statistic

Since we have all the info requires we can replace in formula (1) like this:

$z=\frac{0.540-0.5}{\sqrt{\frac{0.5(1-0.5)}{1000}}}=2.53$

4) Statistical decision

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.

The significance level provided $\alpha=0.01$ . The next step would be calculate the p value for this test.

Since is a right tailed test the p value would be:

$p_v =P(Z>2.53)=0.0057$

So the p value obtained was a very low value and using the significance level given $\alpha=0.01$ we have $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 1% of significance the true proportion is not significantly higher than 0.5.

7 0

3 years ago