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nadezda [96]
3 years ago
15

A basketball player's total points scored for the season went from 158 to 231 over a period of 5 games. What was his scoring rat

e per game over those 5 games?
Mathematics
1 answer:
Len [333]3 years ago
6 0

Answer:

14.6

Step-by-step explanation:

(231 - 158) / 5 = 14.6

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Consider the sequence 1, –3, 9, –27, 81, … Which statement describes the sequence?
ludmilkaskok [199]

Answer:

There is a similar problem with the same numbers except with no negatives so it goes 1 , 3 , 9 , 27, 81 for this question the answer is that it diverges.

Step-by-step explanation:

It was on the unit test review for edge and the answer was that it diverges.

8 0
3 years ago
Read 2 more answers
Will mark brainly :)
WARRIOR [948]

Answer:

If is positive, then the parabola opens upward, so the function decreases on and increases on . But if is negative, then just the reverse

7 0
2 years ago
if a rental car costs Caden $35 for the day, plus $0.33 per mile and his total bill was $78, how many miles did he drive?​
Digiron [165]
78-35= 43
43/.33= 130.30

130.3 miles
7 0
2 years ago
Records indicate that for parts coming out a hydraulic repair shop at an airplane rework facility, 30\% will have a shaft defect
mrs_skeptik [129]

Answer:

P(A|B) = P(A∩B)/P(B) = 100%

Which means that there is 100% probability that the item has at least one type of defect given that the item has only a shaft defect.

Step-by-step explanation:

Conditional probability P(A|B) can be expressed as;

P(A|B) = P(A∩B)/P(B) .....1

Given;

30% will have a shaft defect,

15% will have a bushing defect,

and 65% will be defect-free

Total probability = 100% = P(shaft or/and bushing defect) + P(defect free)

P(shaft or/and bushing defect) = 100% - P(defect free)

= 100% - 65% = 35%

And

P(shaft or/and bushing defect) = P(shaft def only) + P(bushing def only) + P(shaft and bushing defect)

P(shaft or/and bushing defect) = P(shaft defect) + P(bushing defect) - P(shaft and bushing defect)

Substituting the values we have;

35% = 30% + 15% - P(shaft and bushing defect)

P(shaft and bushing defect) = 45% - 35% = 10%

Let A="The item has at least one type of defect"; and B="The item has only a shaft defect".

P(A) = P(shaft or/and bushing defect) = 35%

P(B) = P(shaft only defect) = 30% - 10% = 20%

P(A∩B) = 20%

Substituting into equation 1

P(A|B) = P(A∩B)/P(B) = 20%/20%

P(A|B) = 1/1 = 100%

Which means that there is 100% probability that the item has at least one type of defect given that the item has only a shaft defect.

5 0
3 years ago
which linear system has been correctly solved for one of the variables from the following system? 2x - y = -1 2x y = -7 2x - y =
mr Goodwill [35]
If you would like to solve the system of linear equations, you can do this using the following steps:

2x - y = -1 ... y = 2x + 1
2x + y = -7 ... y = -7 - 2x

The correct result would be: y = 2x + 1, <span>2x + y = -7.</span>
4 0
3 years ago
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