Answer:
The wire is approximately 42feet long
Step-by-step explanation:
We can mentally sketch out the shape that is formed between the guy wire and the antenna tower. This is simply a right-angled triangle with the opposite side being the height of the antenna (30 feet). The adjacent side is the distance on the ground between the point where the wire was fastened and the base of the antenna.
The hypotenuse side is the length of the wire we are looking for.
Parameters are given as:
Opposite : 30ft
Adjacent: 30ft
Hypotenuse: x feet
The hypotenuse = 
Hypotenuse =
Answer:
The variable, y is 11°
Step-by-step explanation:
The given parameters are;
in triangle ΔABC; 
in triangle ΔFGH;
Segment 
= 14 Segment 
= 14
Segment 
= 27 Segment 
= 19
Segment 
= 19 Segment 
= 2·y + 5
∡A = 32° ∡G = 32°
∡A = ∠BAC which is the angle formed by segments = 14 and = 19
Therefore, segment = 27, is the segment opposite to ∡A = 32°
Similarly, ∡G = ∠FGH which is the angle formed by segments = 14 and = 19
Therefore, segment = 2·y + 5, is the segment opposite to ∡A = 32° and triangle ΔABC ≅ ΔFGH by Side-Angle-Side congruency rule which gives;
≅ by Congruent Parts of Congruent Triangles are Congruent (CPCTC)
∴ = = 27° y definition of congruency
= 2·y + 5 = 27° by transitive property
∴ 2·y + 5 = 27°
2·y = 27° - 5° = 22°
y = 22°/2 = 11°
The variable, y = 11°
Answer:
B
Step-by-step explanation:
no need to explain
hope it helps
the fractions are set up so that each unit cancels out until its only meters/hour
you can multiply all the numerators together to get 72000 and all the denominators to get 1
72000 meters/1 hour
72000 meters in 1 hour
hope this helped
