Question

HELPPP PLEASEEE!!! Find the perimeter of ΔTAP with vertices T(1, 4), A(4,4), and P(3,0) to the nearest tenth unit.

Answer 1

Answer: 11.6 units.

Step-by-step explanation:

1. Plot the points as you can see in the graph attached.

2. As you can see, the lenght TA is 3 units.

3. Apply the formula for calculate the distance between two points, to calculate the length TP and TA. The formula is:

$d=\sqrt{(x_2-x_1)^{2}+(y_2-y_1)^{2}}$

4. Therefore, you have:

$TP=\sqrt{(1-3)^{2}+(4-0)^{2}}=4.47units$

$AP=\sqrt{(4-3)^{2}+(4-0)^{2}}=4.12units$

5. The perimeter is the sum of the the lenght of each side, therefore:

$Perimeter=3units+4.47units+4.12units\\Perimeter=11.59units$

6. To the nearest tenth unit:

$Perimeter=11.6units$