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Paha777 [63]
3 years ago
11

Amara wants to draw isosceles right triangles on a coordinate plane that have two vertices at (-2,4) and (5,4). If the coordinat

es of the third vertex are both integers, how many different isosceles right triangles can she draw?
Fill in the banks to explain your reasoning.
For the right triangle to be isosceles and have both coordinates of the third
vertex be integers, a side from one of the two given vertices to the third vertex
must have a length of _____ units and be parallel to the ___-axis.
The y-coordinate for the third vertex must be _____ or _____.

Amara can draw ____ isosceles right triangle(s).
Mathematics
1 answer:
Veseljchak [2.6K]3 years ago
8 0

Answer:

The side must have a length of <u>7</u> units

and be parallel to the <u>y</u>-axis

The y-coordinate for the third vertex must be <u>-3</u> or <u>11</u>

He can draw <u>4</u> isosceles right triangles

Step-by-step explanation:

∵ The side joining (-2 , 4) and (5 , 4) is horizontal (same y-coordinates)

∴ Its length = 5 - 2 = 7

∴ The side from the one of the two given vertices to the third

   vertex must be vertical so it's parallel to the y-axis

∴ The x-coordinate will be -2 or 5

∵ The distance between the y-coordinates of the third vertex

   and one of the given point is 7

∴ 4 - y = 7 ⇒ y = 4 - 7 = -3

∴ y - 4 = 7 ⇒ y = 4 + 7 = 11

∴ The y-coordinate of the third vertex must be -3 or 11

∴ The third vertex is (-2 , -3) , (-2 , 11) , (5 , -3) , (5 , 11)

∴ Amara can draw 4 isosceles right triangles

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ioda

Answer:

8 is thy answer

Step-by-step explanation:

4 0
3 years ago
Giving a test to a group of students, the grades and gender are summarized below
Anna007 [38]

Answer:

46/ 67

Step-by-step explanation:

The numbers of students irrespective of grades is;

The sum of the last roll of numbers:

10+24+ 33+ 67 = 134

The number of males irrespective of grades is the sum of the numbers in the male row ;

7 +20+ 14 +41= 82

The numbers of students with grade A is the first column at the last row and is 10;

Hence;

the probability that the student was male OR got an 'A' is

the probability that the student was male plus the probability that he/she got an 'A'.

The probability that it's a male is ;

Number of males/ total number of students

=82/134

The probability that he got an A is;

The number of students that got A/ the total number of students;

10/134

Hence

the probability that the student was male OR got an 'A' is;

82/ 134 + 10/134 = 92/134 = 46/ 67

5 0
3 years ago
Make x the subject of y = 3x - 2​
BARSIC [14]

Answer:

<h2>x=y+2/3</h2>

Step-by-step explanation:

y=3x-2

+2

y+2=3x

divide by 3

y+2/3=x

8 0
2 years ago
How do I determine if a limit exist considering how it looks on a graph? Can I determine if a limit exists solely from the graph
Allushta [10]

Answer: See below

Step-by-step explanation:

1. At x=1, the limit does not exist. If you see an open circle on the graph like you do here, you know that the function is discontinuous. This graph actually shows a jump discontinuity at x=1.

2.  You can determine if a limit exists by solely looking at the graph. Unfortunately in this case, f(1)=1 and \lim_{x \to \ 1^-} f(x) are not equal to each other. Therefore, the limit does not exist.

7 0
3 years ago
{ y=x−7
Marysya12 [62]
Substitute value of y from equation 1st into 2nd, 
5x + 2y = 7
5x + 2(x - 7) = 7
5x + 2x - 14 = 7
7x = 7 + 14
x = 21 / 7
x = 3

Now, y = 3 - 7 = -4

In short, Your Answer would be Option B) (3, -4)

Hope this helps!
4 0
3 years ago
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