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frozen [14]
3 years ago
15

Write each of the following expressions without using absolute value. 7m–56|, if m<8

Mathematics
1 answer:
egoroff_w [7]3 years ago
3 0

Answer:

|7m- 56| = 56 - 7m

Step-by-step explanation:

Given

|7m- 56|

m < 8

Required

Rewrite the expression without absolute values

The first step is to check if the expression in |...| is positive or negative;

The question says m < 8,

This means the value of m could be 7, 6 ...

Let's assume m is 7

7m - 56 = 7 * 7 - 56 = 49 - 56 = -7

This means that the expression |7m- 56| will give a negative value if m < 8

So,

|7m- 56| = -(7m - 56)

Open bracket

|7m- 56| = -7m + 56

Rearrange

|7m- 56| = 56 - 7m

<em>The expression can't be further simplified</em>

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1) Solving the term (3x + 5)(2x - 3) using F.O.I.L we get \mathbf{6x^2+x-15}

2) solving the term (x + 2)(x - 13) using F.O.I.L we get \mathbf{x^2-11x-26}

3) Solving (x+5)^2 using square of binomial we get \mathbf{x^2+10x+25}

4) Solving (x+5)^2 using square of binomial we get \mathbf{x^2-6x+9}

Step-by-step explanation:

1) (3x + 5)(2x - 3). Solve using the F.O.I.L.

F.O.I.L stands for First, Outer Inner Last

We have (3x + 5)(2x - 3)

First: 3x(2x)

Outer: 3x(-3)

Inner: 5(2x)

Last: 5(-3)

Solving we get:

(3x + 5)(2x - 3)\\=3x(2x)+3x(-3)+5(2x)+5(-3)\\=6x^2-9x+10x-15\\=6x^2+x-15

So, solving the term (3x + 5)(2x - 3) using F.O.I.L we get \mathbf{6x^2+x-15}

2) (x + 2)(x – 13). Solve using the F.O.I.L.

F.O.I.L stands for First, Outer Inner Last

We have (x + 2)(x -13)

First: x(x)

Outer: x(-13)

Inner: 2(x)

Last: 2(-13)

Solving we get:

(x + 2)(x - 13)\\=x(x)+x(-13)+2(x)+2(-13)\\=x^2-13x+2x-26\\=x^2-11x-26

So, solving the term (x + 2)(x - 13) using F.O.I.L we get \mathbf{x^2-11x-26}

3) (x + 5)^2. Solve using the square of Binomial.

The square of binomial is: (a+b)^2=a^2+2ab+b^2

Solving:

(x+5)^2\\=(x)^2+2(x)(5)+(5)^2\\=x^2+10x+25

So, solving (x+5)^2 using square of binomial we get \mathbf{x^2+10x+25}

4) (x -3)^2. Solve using the square of Binomial.

The square of binomial used is: (a-b)^2=a^2-2ab+b^2

Solving:

(x-3)^2\\=(x)^2-2(x)(3)+(3)^2\\=x^2-6x+9

So, solving (x+5)^2 using square of binomial we get \mathbf{x^2-6x+9}

5 0
3 years ago
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