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Len [333]
3 years ago
9

Find all solutions of the equation in the interval [0,2π) sec(theta) +2=0

Mathematics
1 answer:
Komok [63]3 years ago
6 0
I will first reveal the most obvious secret of trig: Most of the problems are 30/60/90 or 45/45/90 triangles of some sort.

\sec \theta + 2  = 0

\dfrac{1 }{ \cos \theta} = -2

\cos \theta = - \frac 1 2

The rule to remember is \cos x = \cos a has solutions

x = \pm a + 2 \pi k \quad integer k

Continuing where we left off, a cosine of -1/2 is a 30/60/90 triangle in the second or third quadrant; we pick second, and a little thought tells us the angle is  120^\circ.

\cos \theta = - \frac 1 2

\cos \theta = \cos \frac {2\pi} 3

\theta = \pm \frac {2\pi} 3 + 2 \pi k \quad integer k

In the range we want, that's k=0 with the plus sign and k=1 with the minus, so 

\theta = \frac {2\pi} 3 or -\frac {2\pi} 3 + 2 \pi = \frac{4 \pi} 3

\theta = \frac {2\pi} 3 or \frac{4 \pi} 3
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3 years ago
What is the multiplicative rate of change of the exponential function represented in the table
stepan [7]
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2 years ago
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Line L passes through the points (0, --3) and (6,9).<br> (a) Find the equation of line L.
valentina_108 [34]

Step-by-step explanation:

Given points are :

(0,\:-3)=(x_1,\:y_1) \:\&\: (6,\:9)=(x_2 ,\:y_2)

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\frac{y -y_1 }{y_1 -y_2 }  = \frac{x -x_1 }{x_1 -x_2 }  \\  \\  \therefore \frac{y -( - 3)}{ -3  -9 }  = \frac{x -0 }{0 -6 }  \\  \\  \therefore \frac{y  + 3}{ -12}  = \frac{x  }{ -6 }  \\  \\  \therefore \frac{y  + 3}{ 2}  = \frac{x  }{1}  \\  \\  \therefore  \: y + 3 = 2x \\  \\  \huge \red{ \boxed{\therefore  \: 2x - y - 3 = 0}} \\ is \: the \: required \: equation \: of \: line.

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3 years ago
How many solutions does the equation −3x−17=−17−3x have?
harkovskaia [24]

Answer:

an infinite number of solutions

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−3x −17 = −17 −3x

left side = right side  TRUE because -3x-17 is the same as -17-3x

we can rearrange  the the equation

−3x −17 +17 = −17 +17−3x, add 17 on both sides of the equations

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               x = x

Since this equation is <u>always true ( for any number ) </u>we have <u>an infinite number of solutions</u> (since there are is an infinity of numbers.)

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///)(;-(()3)3)3$$/$1(-(-(-((1;1;/;;/ ye ya “3
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