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3 years ago

Please help! anyone........

Mathematics

1 answer:

larisa [96]3 years ago

7 0

Answer:

cf=f*points

Step-by-step explanation:

30*1=30

40*2=80

50*4=200

60*3=180

70*3=210

80*5=400

90*6=540

total=sum of all

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What is the answer to this problem 90-40.74

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Read 2 more answers

12% of children are nearsighted, but this condition often is not detected until they go to kindergarten. A school district tests

Klio2033 [76]

Answer:

There is a 34.60% probability that 0 or 1 of them is nearsighted.

Step-by-step explanation:

For each children, there are only two possible outcomes. Either they are nearsighted, or they are not. This means that we can solve this problem using the binomial probability distribution.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinatios of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

In this problem, we have that:

12% of children are nearsighted. This means that $p = 0.12$ .

A school district tests all incoming kindergarteners' vision. In a class of 18 kindergarten students, what is the probability that 0 or 1 of them is nearsighted?

There are 18 students, so $n = 18$

This probability is:

$P = P(X = 0) + P(X = 1)$

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 0) = C_{18,0}.(0.12)^{0}.(0.88)^{18} = 0.1002$

$P(X = 1) = C_{18,1}.(0.12)^{1}.(0.88)^{17} = 0.2458$

$P = P(X = 0) + P(X = 1) = 0.1002 + 0.2458 = 0.3460$

There is a 34.60% probability that 0 or 1 of them is nearsighted.

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3 years ago

Ifyou are asked to solve a system ofequations in which there is no linear equation to start with, you can sometimes begin by iso

maw [93]

What you typped is correct

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3 years ago

If f(x) = 7x^2 - 3x +1 and g(x) = 3x - 2, find the following by matching.

Cloud [144]

f(x) = 7x² - 3x + 1

g(x) = 3x - 2

1. g(0) This means that x is 0, so you can plug in 0 for x in the equation:

g(x) = 3x - 2

g(0) = 3(0) - 2

g(0) = -2

2. g(1) x is 1

g(x) = 3x - 2

g(1) = 3(1) - 2

g(1) = 3 - 2

g(1) = 1

3. f(1) x is 1

f(x) = 7x²- 3x + 1

f(1) = 7(1)² - 3(1) + 1

f(1) = 7 - 3 + 1

f(1) = 5

4. f(x) = 7x²- 3x + 1

f(-2) = 7(-2)²- 3(-2) + 1

f(-2) = 7(4) + 6 + 1

f(-2) = 28 + 7

f(-2) = 35

4 0

3 years ago