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Likurg_2 [28]
2 years ago
14

During a 5% off sale Diego pays $74.10 for a new hockey stick what was the original price

Mathematics
1 answer:
zalisa [80]2 years ago
7 0

Answer:

3.705

Step-by-step explanation:

do 5% of 74.10

tell me if you get it right!!! :)

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Melody spent 16 days traveling in South America. How many weeks and days did Melody travel in South America?
Genrish500 [490]

Answer: 2 week and 2 days

Step-by-step explanation:

Given

Melody spent 16 days in South America

A week consists of 7 days

In 2 weeks it is, 14 days

So, 16 days is equivalent to 2 weeks and 2 days

Melody spent 2 weeks and 2 days in South America

4 0
3 years ago
If r = 8 units and h = 5 units, what is the volume of the cylinder shown above? Use 3.14 for . A. 1,607.68 cubic units B. 653.12
soldier1979 [14.2K]

Answer:

<h2>C. 1,004.8 cubic units</h2>

Step-by-step explanation:

V = ?\\r = 8\\h =5 \\\pi = 3.14\\\\V = \pi r^2 h\\\\V = 3.14 \times 8^2 \times 5\\V = 1004.8 cubic units

6 0
3 years ago
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Plz find the slope plzzzz
e-lub [12.9K]

Answer:

The slope would be rise over run so you go from point A and rise 4 then go over 8

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Step-by-step explanation:

3 0
3 years ago
A bank account yields 7 percent interest, compounded annually. If you deposit $1,000 in the account, what will the account balan
lianna [129]
Hi there
The formula is
A=p (1+r)^t
A future value?
P present value 1000
R interest rate 0.07
T time 5 years
So
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It's a

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7 0
3 years ago
Math question
strojnjashka [21]

Answer:

The candle has a radius of 8 centimeters and 16 centimeters and uses an amount of approximately 1206.372 square centimeters.

Step-by-step explanation:

The volume (V), in cubic centimeters, and surface area (A_{s}), in square centimeters, formulas for the candle are described below:

V = \pi\cdot r^{2}\cdot h (1)

A_{s} = 2\pi\cdot r^{2} + 2\pi\cdot r \cdot h (2)

Where:

r - Radius, in centimeters.

h - Height, in centimeters.

By (1) we have an expression of the height in terms of the volume and the radius of the candle:

h = \frac{V}{\pi\cdot r^{2}}

By substitution in (2) we get the following formula:

A_{s} = 2\pi \cdot r^{2} + 2\pi\cdot r\cdot \left(\frac{V}{\pi\cdot r^{2}} \right)

A_{s} = 2\pi \cdot r^{2} +\frac{2\cdot V}{r}

Then, we derive the formulas for the First and Second Derivative Tests:

First Derivative Test

4\pi\cdot r -\frac{2\cdot V}{r^{2}} = 0

4\pi\cdot r^{3} - 2\cdot V = 0

2\pi\cdot r^{3} = V

r = \sqrt[3]{\frac{V}{2\pi} }

There is just one result, since volume is a positive variable.

Second Derivative Test

A_{s}'' = 4\pi + \frac{4\cdot V}{r^{3}}

If \left(r = \sqrt[3]{\frac{V}{2\pi}}\right):

A_{s} = 4\pi + \frac{4\cdot V}{\frac{V}{2\pi} }

A_{s} = 12\pi (which means that the critical value leads to a minimum)

If we know that V = 3217\,cm^{3}, then the dimensions for the minimum amount of plastic are:

r = \sqrt[3]{\frac{V}{2\pi} }

r = \sqrt[3]{\frac{3217\,cm^{3}}{2\pi}}

r = 8\,cm

h = \frac{V}{\pi\cdot r^{2}}

h = \frac{3217\,cm^{3}}{\pi\cdot (8\,cm)^{2}}

h = 16\,cm

And the amount of plastic needed to cover the outside of the candle for packaging is:

A_{s} = 2\pi\cdot r^{2} + 2\pi\cdot r \cdot h

A_{s} = 2\pi\cdot (8\,cm)^{2} + 2\pi\cdot (8\,cm)\cdot (16\,cm)

A_{s} \approx 1206.372\,cm^{2}

The candle has a radius of 8 centimeters and 16 centimeters and uses an amount of approximately 1206.372 square centimeters.

3 0
3 years ago
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