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dolphi86 [110]
3 years ago
10

Is 6.1 an rational number?

Mathematics
1 answer:
Bezzdna [24]3 years ago
6 0
Yes it is because it ends
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Factoring Quadratic Expressions:<br> 5p^2 - p - 18
VMariaS [17]
5p² - p - 18 = (5p +9)(p - 2)
7 0
3 years ago
A TV set contains five circuit boards of type A, five of type B, and four of type C. The probability of failing in its first 500
Aleks04 [339]

Answer:

0.903264

Step-by-step explanation:

Given that a TV set contains five circuit boards of type A, five of type B, and four of type C. The probability of failing in its first 5000 hours of use is 0.03 for a type A circuit board, 0.04 for a type B circuit board, and 0.03 for a type C circuit board.

Let A' = the event that A fails, B' =  B fails and C'= C fails.

Probability that no circuit board fails = Prob (A'B'C')

= P(A')P(B')P(C')  (since A,B, C are independent, their complements are independent

= (1-0.03)(1-0.04)(1-0.03)

= 0.903264

4 0
4 years ago
PLEASE HELP ASAP !!!!<br><br><br> Explain Larissa's mistake using 1-3 complete sentences.
kenny6666 [7]

Answer:

Line 6

Step-by-step explanation:

The graph intersects at (-5, 16) and (2, 2)

Because she needs to plug the x's back into the equation

so  16 = -2(-5) + 6  or  16 = -5^{2} + -5 - 4

and  2 = -2(2) + 6  or  2 = 2^{2} + 2 - 4

4 0
3 years ago
Multiply 3/4 x 16/19
Nataly_w [17]

Answer:

12/19 or 0.6315

Step-by-step explanation:

You see that the denominator of 3/4 is 4 and the numerator of 16/19 is 16 both 4 and 16 are common factors, so you can reduce this to 3x4/19 then multiply 3/1 x 4/19 to give you 12/ 19 because 3x4 is 12 and 1x19 is 19.

8 0
3 years ago
Solve the equation and show all work. 4|x + 1/3| = 20 <br> i'm kind of stuck hhh
34kurt

Absolute value is a function that takes some number and outputs the size of that number, regardless of the sign. By definition, |x|=x if x\ge0, and |x|=-x if x.

For example,

  • |2| = 2 because the input 2 is positive, so the input is unchanged;
  • |-3| = -(-3) = 3 because the input -3 is negative, so the sign is switched.

What this means for this problem is that there are two cases to consider:

  • If x+\frac13\ge0, then \left|x+\frac13\right|=x+\frac13, so that

4\left(x+\dfrac13\right)=20\implies x+\dfrac13=5\implies\boxed{x=\dfrac{14}3}

  • On the other hand, if x+\frac13, then \left|x+\frac13\right|=-\left(x+\frac13\right), so

-4\left(x+\dfrac13\right)=20\implies x+\dfrac13=-5\implies\boxed{x=-\dfrac{16}3}

6 0
4 years ago
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