How can you prove a quadrilateral on a coordinate plane is a parallelogram?

1 answer:

6 0

To prove that it is a parallelogram, remember that the definition of a parallelogram is a quadrilateral with two pairs of parallel sides. Therefore, one way to prove it is a parallelogram is to verify that the opposite sides are parallel. From algebra, remember that two lines are parallel if they have the same slope.

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What is the nth term to: 27,25,23,21,19

nlexa [21]

Answer:Tn=29-2n

Step-by-step explanation:

Firstly u determine the differences between the terms and see if it's common. These case the common difference is -2 which means these is a linear pattern.

Now Tn=a+(n-1)d

Tn=27+(n-1)(-2)

Tn=27-2n+2

Tn=29-2n

8 0

3 years ago

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Please help me on my GEOMETRY question

GuDViN [60]

∠ABX is an inscribed angle.
The measure of an inscribed angle is half the measure of the intercepted arc ⇒
arc AX = 2*∠ABX = 2 * 64 = 128°

The angle formed by the intersection of tangent and secant outside the circle equals half the difference of the intercepted arcs ⇒
∠ACB = (arc AB - arc AX)/2 = (152 - 128)/2 = 24/2 = 12°

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3 years ago

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The diagram shows a right-angled triangle.

son4ous [18]

answer

11.3 cm

steps

what is h cm to angle 37°=it is an opposite side

what is 15 cm to angle 37°=it is an adjecent side

opposite and adjecent form a tan

.°. opp/adj = tan(37°)

h/15 = tan(37°)

h = 11.3 cm

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3 years ago

If 400 g of chocolate sells for $12, "how much is the cost per kilogram?

Kryger [21]

the cost of the chocolate of 1 kg will be 30$

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Find the missing side of a right triangle with leg length 5 yards and hypotenuse 13 yards.

Roman55 [17]

$answer =12 \: yards \\ solution \\ hypotenuse(h) = 13 \: yards \\ perpendicular(p) = 5 \: yards \\ base(b) = ?\\ using \: pythagorus \: theorem \\ {h}^{2} = {p}^{2} + {b}^{2} \\ {b}^{2} = {h}^{2} - {p}^{2} \\ {b}^{2} = {13}^{2} - {5}^{2} \\ {b}^{2} = 169 - 25 \\ {b}^{2} = 144 \\ b = \sqrt{144 } \\ b = \sqrt{ {12}^{2} } \\ b = 12 \\ hope \: it \: helps \\ good \: luck \: on \: your \: assignment$

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4 years ago

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