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3 years ago

ALL MY POINTS PLZ BE RIGHT

Mathematics

2 answers:

shepuryov [24]3 years ago

7 0

Answer:

-xy^6 +2y -6

Step-by-step explanation:

(-6x^2 y^8+12xy^3-36xy^2)

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6xy^2

Divide each term by 6 in the numerator and denominator

(-6/6x^2 y^8+12/6xy^3-36/6xy^2)

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6/6xy^2

-x^2y^8 +2xy^3 -6xy^2

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xy^2

Divide each term by x in the numerator and denominator

-x^2/xy^8 +2x/xy^3 -6x/xy^2

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x/xy^2

-xy^8 +2y^3 -6y^2

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y^2

Divide each term by y^2 in the numerator and denominator

Remember when dividing, we subtract the exponents

-xy^8/y^2 +2y^3/y^2 -6y^2/y^2

---------------------------------

y^2 /y^2

-xy^6 +2y^1 -6

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-xy^6 +2y -6

Anastaziya [24]3 years ago

7 0

Answer: BBBBBBBBBBBBBBBBBBBBBB

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3 years ago

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2w^2-11w=-12 <br> a w=3/2 or 4<br> b w=1 or 12<br> c w=1 or 7<br> d w = 2.5 or 6

dlinn [17]

Hey mate !!
Here's your answer !!

2w^2 - 11w = -12
2w^2 -11w + 12 = 0
2w^2 - 8w - 3w + 12 = 0

2w ( w - 4) -3 ( w - 4) = 0
(2w - 3) ( w - 4) = 0

Hence

2w - 3 = 0
2w = 3
w = 3/2

w - 4 = 0
w = 4

Hence value of w are 4 and 3/2

Hope this helps!!
Cheers!!

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4 years ago

Which series of transformations will not map figure H onto itself

7nadin3 [17]

Answer:

Step-by-step explanation:

Given a square with vertices at points (2,1), (1,2), (2,3) and (3,2).

Consider option A.

1st transformation $(x+0,y-2)$ will map vertices of the square into points