All categories

3 years ago

What is the equation of this parabola in vertex form

Mathematics

1 answer:

attashe74 [19]3 years ago

6 0

first off, let's notice the parabola is a vertical one, therefore the squared variable is the x, and the parabola is opening upwards, meaning the coefficient of x² is positive.

let's notice the vertex, or U-turn, is at (-2, 2)

$\bf ~~~~~~\textit{parabola vertex form} \\\\ \begin{array}{llll} \boxed{y=a(x- h)^2+ k}\\\\ x=a(y- k)^2+ h \end{array} \qquad\qquad vertex~~(\stackrel{-2}{ h},\stackrel{2}{ k}) \\\\\\ y=+1[x-(-2)]^2+2\implies y=(x+2)^2+2$

You might be interested in

War your work, please.

Goshia [24]

Answer:

1.) 7. (7 x 7 = 9)

2.) IDK, sorry

3.) 8/27

Apply the product rule to 2/3

2^3/ 3^3

Raise 2 to the power of 3.

8/27

4.) 9

1. Exponentiation: 3 ^ 4 = 81

2. Exponentiation: 3 ^ (-2) = 0.111111111111 = 1/9

3. Multiple: the result of step No. 1 * the result of step No. 3 = 81*1/9 = 81 · 1/1 · 9 = 81/9 = 9 · 9/1 · 9 = 9

Multiply both numerators and denominators. Result fraction keep to lowest possible denominator GCD(81, 9) = 9. Cancelling by a common factor of 9 gives 9/1.

In words - eighty-one multiplied by one ninth = nine.

4. Exponentiation: 3 ^ 0 = 1

5.Multiple: the result of step No. 4 * the result of step No. 5 = 9 * 1 = 9

5.) 1/125

5 ^ (-3) = 0.008 = 1/125

6.) IDK, sorry

7 0

3 years ago

100 blue marbles to 60 red marbles=

Aloiza [94]

So the ratio is 100:60 and that simplified is 5:3. for every 5 blue there is 3 red

4 0

3 years ago

Read 2 more answers

(Score for Question 3: ___ of 5 points)

mote1985 [20]

Here are the step for solving this:
1. 3y + 5 > 23
-5 -5
3y/3 > 18/3
y > 6

In words what you are doing is getting y by itself on one side. Subtract the 5 to undo the adding of 5 first. Then, divide both sides by 3.

7 0

3 years ago

The dwarves of the Grey Mountains wish to conduct a survey of their pick-axes in order to construct a 99% confidence interval ab

Dmitry_Shevchenko [17]

Answer:

The minimum sample size needed is 125.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence level of $1-\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which

z is the zscore that has a pvalue of $1 - \frac{\alpha}{2}$ .

The margin of error is:

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

For this problem, we have that:

$\pi = 0.25$

99% confidence level

So $\alpha = 0.01$ , z is the value of Z that has a pvalue of $1 - \frac{0.01}{2} = 0.995$ , so $Z = 2.575$ .

What minimum sample size would be necessary in order ensure a margin of error of 10 percentage points (or less) if they use the prior estimate that 25 percent of the pick-axes are in need of repair?

This minimum sample size is n.

n is found when $M = 0.1$