Please comment if you have any questions... :)
1/6 of a treat would be your answer
hope this helps
9 - 6 + 4 - 8/3 ..,
geometric series a(n) = a1r^(n-1)
r = a(n+1)/a(n)
-6/9 = -2/3
4/-6 = -2/3
-8/3/4 = -2/3
so r = -2/3 and a1 = 9
Sn = a1(1-r^n)/(1-r) = 9(1-(-2/3)^n)/(1-(-2/3))
n is infinite Sn = 9/(5/3) = 27/5
<span>78</span><span>(16)</span><span>=<span><span>(<span>78</span>)</span><span>(<span>161</span>)</span></span></span><span>=<span><span><span>(7)</span><span>(16)</span></span><span><span>(8)</span><span>(1)</span></span></span></span><span>=<span>1128</span></span><span>=14</span>
