Y=x^2
substitute the values into the original equation
0=4^2
0=16
No it does not satisfy the equation because 0 does not equal to 16
= 1/2 (a + b) h let me know if this helps :)
Answer:
Option A, -15
Step-by-step explanation:
<u>Step 1: Look at the function that needs to be outputted when x = -3</u>
Since x = -3, that means it falls into the first category of x ≤ -3
<u>Step 2: Carry out the instructions</u>
The function for the first category is 



Answer: Option A, -15