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3 years ago

Which point lies on the graph of the equation 10y = 3x - 11?

Mathematics

1 answer:

GaryK [48]3 years ago

5 0

Answer:

A. (2,-0.5)

Step-by-step explanation:

A pair of coordinates is always (x,y) so

If you insert the numbers into the equation you get

10(-0.5) = 3(2) - 11

-5 = 6 - 11

-5 = -5

Therefore (2,-0.5) is the point that likes on the graph

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A color printer prints 23 pages in 9 minutes. How many pages does it print per minute? Round to the nearest hundredth. No links

never [62]

Answer:

2.56

Step-by-step explanation:

To find out how many pages the printer prints per minute, you need to divide the amount of pages it printed with how long it printed.

So 23÷9

Which equals 2.55555555-

Round 2.5555555 to the nearest hundredth you get 2.56.

3 0

3 years ago

Read 2 more answers

Please help me with this!!

NeTakaya

Answer:

Step-by-step explanation:

a. true because there are 0 cookies in the box at that point

b. true because the slope is the average weight of a cookie

c. false because the number of cookies will determine the weight of the box

d. false the box is 1oz and box+1 cookie=1.25 oz so the cookie is 1.25-1= .25oz

e. true if you continue the line until 13 cookies you have about 3.75oz

8 0

3 years ago

F $1,000 is deposited in a certain bank account and remains in the account along with any accumulated interest, the dollar amoun

Whitepunk [10]

Answer:

(1) The annual interest rate is 10%, that is greater than 8%

(2) The annual interest is bigger than 22.47% and that is greater than 8%

Step-by-step explanation:

We have the equation:

$I=1,000((1+\frac{r}{100} )^{n} -1)$

Where I is the earns in interest, n is the number of years and r is the annual interest rate.

For the first case, we can replace I by $210 and n by 2 as:

$210=1,000((1+\frac{r}{100} )^{2} -1)$

Solving for r, we get:

$\frac{210}{1,000} = (1+\frac{r}{100})^{2} -1$

$0.21 +1 = (1+\frac{r}{100})^{2}$

$1.21 = (1+\frac{r}{100})^{2}$

$\sqrt{1.21} = 1 + \frac{r}{100}$

$\sqrt{1.21} - 1 = \frac{r}{100}$

$(\sqrt{1.21} - 1)100=r$

$10=r$

So, for the first case, the interest rate paid by the bank is 10% and it is greater than 8%

For the second case, we need to take the equation and solve for r as:

$(1+\frac{r}{100} )^{2} >1.5$

$1+\frac{r}{100} > \sqrt{1.5}$

$\frac{r}{100} > \sqrt{1.5}-1$

$r > (\sqrt{1.5}-1)*100$

$r > 22.47$

So, for the second case the rate need to be bigger than 22.47% and that is bigger than 8%

5 0

3 years ago

Please help me with my math hw

vlabodo [156]

Selling Price Cost Profit Mark up 
 75.99 61.00 14.99 0.25
 29.95 23.75 6.20 0.26
 19.25 15.00 4.25 0.28
 1.50 1.19 0.31 0.26
 54.99 44.55 10.44 0.23
 12.95 10.80 2.15 0.20

Profit = Selling price - Cost
Mark up = Profit / cost

4 0

3 years ago

The answer for this I need it

laila [671]

The answer to the question is b

5 0

4 years ago