The sum of 4 consecutive integers is 122. What is the third number in this sequence?
1 answer:
Answer:
31
Step-by-step explanation:
Let the smallest integer be x.
Since the 4 integers are consecutive (they come right after the other),
2nd integer= x +1
3rd integer= x +1 +1= x +2
4th integer= x +2 +1= x +3
Sum of the integers= 122
x +x +1 +x +2 +x +3= 122
4x +6= 122
4x= 122 -6
4x= 116
x= 116 ÷4
x= 29
3rd number
= 29 +2
= 31
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