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3 years ago

A point lies on AB and is the distance from A to B. Point A is located at (4, 8) and point B is located at (14, 10)

Mathematics

1 answer:

Rzqust [24]3 years ago

6 0

Answer:

(9,9)

Step-by-step explanation:

Assuming the point is exactly halfway between A and B, to find it we just need to find the centre point between (4,8) and (14,10).

To find the midpoint, we just need to find the middle value, by dividing the difference between the x values by 2, and repeating the process with the y values.

This is because the point is in the middle, so it's y value will be in the middle of the given AB y values, and its x value will also be directly in the middle of the AB x values.

The x values are 4 and 14. The midpoint is

14-4=10

10/2=5 (the midpoint is 5 away from each reference point)

4+5=9

The midpoint is 9 for the x values. This means the x-value for the point is 9.

Repeat for y-values:

10-8=2

2/2=1

8+1=9

The midpoint is 9, therefore it has the y coordinate of 9.

Therefore the coordinates for the point are (9,9).

Hope this helped!

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Evaluate the definite integral. <br> 1 x4(1 + 2x5)5 dx.

Nata [24]

Answer:

Step-by-step explanation:

Given the definite integral $\int\limits {\dfrac{x^4}{(1-2x^5)^5} } \, dx$ , we to evaluate it. Using integration by substitution method.

Let u = 1-2x⁵ ...1

du/dx = -10x⁴

dx = du/-10x⁴.... 2

Substitute equation 1 and 2 into the integral function and evaluate the resulting integral as shown;

$= \int\limits {\dfrac{x^4}{u^5} } \, \dfrac{du}{-10x^4}$

$= \dfrac{-1}{10} \int\limits {\dfrac{du}{u^5} } \\\\= \dfrac{-1}{10} \int\limits {{u^{-5}du } \\= \dfrac{-1}{10} [{\frac{u^{-5+1}}{-5+1}] \\\\= \dfrac{-1}{10} ({\frac{u^{-4}}{-4})\\\\$

$= \dfrac{u^{-4}}{40} \\\\\\= \dfrac{1}{40u^4} +C$

substitute u = 1-2x⁵ into the result

$= \dfrac{1}{40(1-2x^5)^4} +C$

Hence $\int\limits {\dfrac{x^4}{(1-2x^5)^5} } \, dx$ $= \dfrac{1}{40(1-2x^5)^4} +C$

5 0

2 years ago

Please help me in this questions....

Ivahew [28]

Part (i)

I'm going to use the notation T(n) instead of $T_n$

To find the first term, we plug in n = 1

T(n) = 2 - 3n

T(1) = 2 - 3(1)

T(1) = -1

The first term is -1

Repeat for n = 2 to find the second term

T(n) = 2 - 3n

T(2) = 2 - 3(2)

T(2) = -4

The second term is -4

<h3>Answers: -1, -4</h3>

==============================================

Part (ii)

Plug in T(n) = -61 and solve for n

T(n) = 2 - 3n

-61 = 2 - 3n

-61-2 = -3n

-63 = -3n

-3n = -63

n = -63/(-3)

n = 21

Note that plugging in n = 21 leads to T(21) = -61, similar to how we computed the items back in part (i).

<h3>Answer: 21st term</h3>

===============================================

Part (iii)

We're given that T(n) = 2 - 3n

Let's compute T(2n). We do so by replacing every copy of n with 2n like so

T(n) = 2 - 3n

T(2n) = 2 - 3(2n)

T(2n) = 2 - 6n

Now subtract T(2n) from T(n)

T(n) - T(2n) = (2-3n) - (2-6n)

T(n) - T(2n) = 2-3n - 2+6n

T(n) - T(2n) = 3n

Then set this equal to 24 and solve for n

T(n) - T(2n) = 24

3n = 24

n = 24/3

n = 8

This means 2n = 2*8 = 16. So subtracting T(8) - T(16) will get us 24.

<h3>Answer: 8</h3>

4 0

3 years ago

Thr four angles of a quadrilateral L are in the ratio 5:2:3:8find the angle

Anuta_ua [19.1K]

Ratio = 5:2:3:8
Sum of all internal angles = 360°
5x + 2x + 3x + 8x = 360°
18x = 360°
x = 20°
Therefore,
5x = 100°
2x = 40°
3x = 60°
8x = 160°
5:2:3:8 :: 100:40:60:160.

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