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3 years ago

A gardener is planting two types of trees:

Mathematics

1 answer:

ICE Princess25 [194]3 years ago

5 0

Answer:

After 1 year, both the tress will be of the same height.

Step-by-step explanation:

Let us assume in x years, both trees have same height.

Type A is 7 feet tall and grows at a rate of 8 inches per year.

⇒The growth of tree A in x years = x times ( Height growth each year)

= 8 (x) = 8 x

⇒Actual height of tree A in x years = Initial Height + Growth in x years

= 7 + 8 x

or, the height of tree A after x years = 7 + 8x

Type B is 9 feet tall and grows at a rate of 6 inches per year.

⇒The growth of tree B in x years = x times ( Height growth each year)

= 6 (x) = 6 x

⇒Actual height of tree B in x years = Initial Height + Growth in x years

= 9 + 6 x

or, the height of tree B after x years = 9 + 6x

According to the question:

After x years, Height of tree A =Height of tree B

⇒7 + 8x = 9 + 6x

or, 8x - 6x = 9 - 7

or, 2 x = 2

or, x = 2/2 = 1 ⇒ x = 1

Hence, after 1 year, both the tress will be of the same height.

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tamaranim1 [39]

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4 years ago

Matthew is making a sequence in which -3 is added to each successive term. The 6th term in his sequence is -1. What is the 1st t

Hatshy [7]

Answer:

The first term is 14.

Step-by-step explanation:

The general formula for this kind of sequence (arithmetic) is a(n) = a(1) + (n-1)c, where c is the common difference. Here, we have a(6) = -1 = a(1) + (6-1)(-3), or -1 +15 = a(1). The first term is 14.

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3 years ago

☆pls help no one has helped me and I'm so confused!

motikmotik

Answer:

Step-by-step explanation:

a). $\frac{5\pm\sqrt{-4}}{3}$ = $\frac{5}{3}\pm \frac{\sqrt{-4}}{3}$

= $\frac{5}{3}\pm\frac{2\sqrt{(-1)} }{3}$

= $\frac{5}{3}\pm\frac{2i}{3}$ [Since, i = $\sqrt{(-1)}$ ]

b). $\frac{10\pm\sqrt{-16}}{2}$ = $\frac{10}{2}\pm \frac{\sqrt{-16}}{2}$

= $5\pm \frac{4\sqrt{-1}}{2}$

= 5 ± 2i [Since, i = $\sqrt{(-1)}$ ]

c). $\frac{-3\pm \sqrt{-144}}{6}$ = $-\frac{3}{6}\pm \frac{\sqrt{-144}}{6}$

= $-\frac{3}{6}\pm \frac{12\sqrt{-1}}{6}$

= $-\frac{1}{2}\pm 2\sqrt{-1}$

= $-\frac{1}{2}\pm 2i$ [Since, i = $\sqrt{(-1)}$ ]

4 0

3 years ago

The range of which function is (2, infinity)? y = 2x y = 2(5x) y = 5x 2 y = 5x 2

vova2212 [387]

The function which has range (2, infinity) from the provided function is y = 5ˣ +2. Option 4 is correct.

<h3>What is range of function?</h3>

Range of a function is the set of all the possible output values which are valid for that function.

The function whose range is (2, ∞) has to be find out.

The first function given in the problem is,

$y=2^x$

This function has the periodic function with period of logarithmic function and the range of this function is all the real number. This is not the correct option.

The second function given in the problem is,

$y=2(5)^x$

This function has the periodic function with period of logarithmic function and the range of this function is all the real number. This is not the correct option.

The fourth function given in the problem is,

$y=(5)^x+2$