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aleksley [76]
3 years ago
11

Find the zeros in the function 3x2+ 6 = 0

Mathematics
1 answer:
sattari [20]3 years ago
5 0

Answer:

x = ± i \sqrt{2}

Step-by-step explanation:

Given

3x² + 6 = 0 ( subtract 6 from both sides )

3x² = - 6 ( divide both sides by 3 )

x² = - 2 ( take the square root of both sides )

x = ± \sqrt{-2}

  = ± \sqrt{2(-1)}

  = ± (\sqrt{2} × \sqrt{-1}) → \sqrt{-1} = i

  = ± i \sqrt{2}

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Answer:

The range is y≥0

Step-by-step explanation:

The shape of this graph is a parabola

You may see this by using the Desmos calculator and typing y=x^2 if you would like to visualize.

(a) The function y = x^2 simply takes whatever number you feed it (x) and outputs x squared.

For example

y = (2)^2=4

y = (3)^2 = 9

(b) To graph x^2 simply make a table of values and plug in 0 -> however high you would like to go ( usually to 5 or so is fine but you could go to infinity).

Example

      y = x^2

                 Y    |     X

                ________

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In this case the function's range is y≥0 because all y values will be greater than or equal to 0.

If you are wanting to learn how to specifically graph this you can look up (Graphing y = x²) if my quick graphing explanation back at mark (b) does not help.

8 0
2 years ago
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SOVA2 [1]

Answer:

  1

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_____

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Here, this means you divide the integral into two parts: one where the integrand is -x/x, and one where it is +x/x.

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Step-by-step explanation:

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