Question

Find the zeros in the function 3x2+ 6 = 0

Answer 1

Answer:

x = ± i $\sqrt{2}$

Step-by-step explanation:

Given

3x² + 6 = 0 ( subtract 6 from both sides )

3x² = - 6 ( divide both sides by 3 )

x² = - 2 ( take the square root of both sides )

x = ± $\sqrt{-2}$

  = ± $\sqrt{2(-1)}$

  = ± ($\sqrt{2}$ × $\sqrt{-1}$) → $\sqrt{-1}$ = i

  = ± i $\sqrt{2}$