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svp [43]
3 years ago
11

What is the solution to this inequality? x-6<-4

Mathematics
1 answer:
9966 [12]3 years ago
8 0

Answer:

x<2

Step-by-step explanation:

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Please help me asap<br><br>​
dimaraw [331]
Okay so basically 1 + 5 = 180
and if we know 1 = 124 we can assume 5 = 56
and 5 = 4 SOOOO
4 = 56
4 0
3 years ago
Find Aut( 15). Use the Fundamental Theorem of Abelian Groups to express this group as an external direct product of cyclic group
Eduardwww [97]

Answer:

The solution is attached in the picture below

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
A local gym instructor has a course load that allows her to teach eight classes. At an interest meeting, 8 people wanted high-­‐
cricket20 [7]

Answer:

<u>The final curse load of the local gym instructor is this:</u>

<u>High-­‐impact aerobics = 1</u>

<u>Low-­‐impact aerobics =  4</u>

<u>Jazzercise = 1</u>

<u>Step exercise = 2</u>

Step-by-step explanation:

1. Let's apportion the class load using the Hamilton method

Number of classes the local gym instructor can teach = 8

Total number of students that want to take a class = 114 (8 people wanted high-­‐impact aerobics, 64 wanted low-­‐impact aerobics, 11 wanted jazzercise, and 31 wanted step exercise)

Standard divisor = 114/8 = 14.25

Now, we can apportion the students in in Standard quotas, this way:

High-­‐impact aerobics = 8/14.25 = 0.5614

Low-­‐impact aerobics = 64/14.25 = 4.49

Jazzercise = 11/14.25 = 0.7719

Step exercise = 31/14.25 = 2.1754

Now, we find the Minimum quota, just considering the whole number and don't taking into account the decimals, this way:

High-­‐impact aerobics = 0

Low-­‐impact aerobics =  4

Jazzercise = 0

Step exercise = 2

As we can see we have 6 classes and there are 2 still pending. Those 2 goes to the classes with the highest decimal portion, in this case, Jazzercise .7719 and High-­‐impact aerobics with .5614.

<u>The final course load is this:</u>

<u>High-­‐impact aerobics = 1</u>

<u>Low-­‐impact aerobics =  4</u>

<u>Jazzercise = 1</u>

<u>Step exercise = 2</u>

7 0
3 years ago
Simplify the expression: 2(4 + 6j)
aniked [119]

Answer:

\boxed{ \bold{ \huge{ \boxed{ \sf{8 + 12j}}}}}

Step-by-step explanation:

\sf{2(4 + 6j)}

Distribute 2 through the parentheses

\longrightarrow{ \sf{2 \times 4  + 2 \times 6j}}

\longrightarrow{ \sf{8  + 12j}}

Hope I helped!

Best regards! :D

8 0
4 years ago
Lowest common multiple of 28 and 42
Delicious77 [7]
7 is the lowest common multiple i think
8 0
4 years ago
Read 2 more answers
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