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EleoNora [17]
4 years ago
15

If D is the midpoint of segment AC , C is the midpoint of segment AB , and AD = 3 cm, what is the length of segment BC ?\

Mathematics
1 answer:
Bogdan [553]4 years ago
3 0

Answer:

6

Step-by-step explanation:

If D is the midpoint of AC, that means that AC = AD * 2 = 3 * 2 = 6. And if C is the midpoint of AB, that means BC = AC = 6.

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Which of the following correctly describes the domain of the function shown
labwork [276]

Option D:

\{x: x \neq 1\} is the domain of the function.

Solution:

Given function is

$r(x)=\frac{2 x}{x-1}

<u>To find the domain of the function:</u>

Option A: \{x: x \neq 0\}

Substitute x = 0 in r(x).

$r(0)=\frac{2 \times 0}{0-1}=0

If x = 0, then r(0) = 0

So that x ≠ 0 is false.

So, \{x: x \neq 0\} is not the domain of the function.

Option B: \{x: x \neq \pm 1\}

Substitute x = –1 in r(x).

$r(-1)=\frac{2 \times (-1)}{-1-1}=1

If x = –1, then r(–1) = 1

So that x = ± 1 is false.

So, \{x: x \neq \pm 1\} is not the domain of the function.

Option C: $\{x: \text { all real numbers }\}$

Substitute x = 1 in r(x).

$r(1)=\frac{2 \times 1}{1-1}=\frac{2}{0}

It is indeterminate.

So, all real numbers are not the domain of the function.

Option D: \{x: x \neq 1\}

Substitute x = 1 in r(x).

$r(1)=\frac{2 \times 1}{1-1}=\frac{2}{0}

It is indeterminate.

So, \{x: x \neq 1\} is the domain of the function.

4 0
3 years ago
Solve the following <br><br><br> C^2-14=5c
kipiarov [429]

Answer:

c = - 2, c = 7

Step-by-step explanation:

Given

c² - 14 = 5c ( subtract 5c from both sides )

c² - 5c - 14 = 0 ← in standard form

To factorise the quadratic

Consider the factors of the constant term (- 14) which sum to give the coefficient of the c- term (- 5)

The factors are - 7 and + 2, since

- 7 × 2 = - 14 and - 7 + 2 = - 5, hence

(c - 7)(c + 2) = 0

Equate each factor to zero and solve for c

c - 7 = 0 ⇒ c = 7

c + 2 = 0 ⇒ c = - 2

8 0
3 years ago
A rectangle has a height of 2 + 9 and a width of x2 + 2x.
Dafna1 [17]

Answer: 40

Step-by-step explanation:

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3 years ago
the angle of elevation from point c to the top of the cliff is 34°. if point c is 1,000 ft from the base of the cliff, how high
Yanka [14]

Answer:

675 ft (3 s.f.)

Step-by-step explanation:

Please see attached picture for full solution.

7 0
3 years ago
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irina [24]

$21.6

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Step-by-step explanation:

Kilometres when Satish is alone

150 kilometres in the beginning

150 kilometres in the end

Total: 300 kilometres

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