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zimovet [89]
3 years ago
9

NEED HELP ASAP PLEASE

Mathematics
1 answer:
Maslowich3 years ago
3 0
 the answer is A. your welcome.


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Help please help help please please please
AnnZ [28]

Answer:

C. \frac{5}{4}

D. \frac{6}{7}

Step-by-step explanation:

C. 2 -  \frac{12}{16}

= 2 -  \frac{3}{4}

=  \frac{8 - 3}{4}

=  \frac{5}{4}

D. \frac{20}{22}  \times  \frac{33}{35}

=  \frac{10}{11}  \times  \frac{33}{35}

= 10 \times  \frac{3}{35}

= 2 \times  \frac{3}{7}

=  \frac{6}{7}

3 0
3 years ago
3. You have spent a total of $440 total on your gym membership so far. If the gym charges a
slava [35]

Answer:

13 months

Step-by-step explanation:

m=number of months

30(m)+50

30*13= 390

390+50=440

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3 years ago
JOIN MY ZOOOm guys! 945 8081 2458 passowrd: Cgx6Nm : all are allowed:)
Ket [755]

Answer: cool!

Step-by-step explanation: ;)

8 0
3 years ago
In Vancouver, British Columbia, the probability of rain during a winter day is 0.42, for a spring day is 0.23, for a summer day
nadezda [96]

Answer:

31.82% probability that this day would be a winter day

Step-by-step explanation:

We use the conditional probability formula to solve this question. It is

P(B|A) = \frac{P(A \cap B)}{P(A)}

In which

P(B|A) is the probability of event B happening, given that A happened.

P(A \cap B) is the probability of both A and B happening.

P(A) is the probability of A happening

In this question:

Event A: Rain

Event B: Winter day

Probability of rain:

0.42 of 0.25(winter), 0.23 of 0.25(spring), 0.16 of 0.25(summer) or 0.51 of 0.25(fall).

So

P(A) = 0.42*0.25 + 0.23*0.25 + 0.16*0.25 + 0.51*0.25 = 0.33

Intersection:

Rain on a winter day, which is 0.42 of 0.25. So

P(A \cap B) = 0.42*0.25 = 0.105

If you were told that on a particular day it was raining in Vancouver, what would be the probability that this day would be a winter day?

P(B|A) = \frac{0.105}{0.33} = 0.3182

31.82% probability that this day would be a winter day

6 0
3 years ago
Please help me out? thank you.
anzhelika [568]
It’s the fourth answer
4 0
3 years ago
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