How do i solve this problem?

Ahat [919]

Solutions

To solve the problem our first step is to find the prime factorization of each number. 

4 = 2²
5 = 5 
6 = 2 x 3

Calculations

LCM = 2² x 3 x 5 = 60

6 0

3 years ago

20 POINT TO THE FIRST ANSWER + BRAINLIEST!!!

love history [14]

The cost of aquiring the source is high, i believe

3 0

3 years ago

. Lightning Strikes It has been said that the probability of being struck by lightning is about 1 in 750,000, but under what cir

mrs_skeptik [129]

Complete Question

The complete question is shown on the first uploaded image

Answer:

a

$P(U |D ) = 0.198$

b

$P(O\ n \ B) = 0.188$

c

$P(O | B) = 0.498$

Step-by-step explanation:

The total number of deaths is mathematically represented as

$T = 16 + 23 + \cdots + 16$

$T =623$

The total number of deaths in 1996 - 2000 is mathematically represented as

$T_a = 16 + 23+ \cdots + 30$

$T_a = 235$

The total number of deaths in 2001 - 2005 is mathematically represented as

$T_b = 17 + 16 + \cdots + 23$

$T_b = 206$

The total number of deaths in 2006 - 2010 is mathematically represented as

$T_c = 15 + 17 + \cdots + 16$

$T_d = 182$

Generally the the probability that it would occur under the tree given that the death was after 2000 is mathematically represented as

$P(U |D ) = \frac{P(A \ n\ U )}{P(A)}$

Here $P(A \ n\ U )$ represents the probability that it was after 2000 and it was under the tree and this is mathematically represented as

$P(A \ n\ U ) = \frac{Z}{ T}$

Here Z is the total number of death under the tree after 2000 and it is mathematically represented as

$Z = 35 + 42$

=> $Z = 77$

=> $P(A \ n\ U ) = \frac{77}{ 623}$

=>

Also

$P(A)$ is the probability of the death occurring after 2000 and this is mathematically represented as

$P(A) = \frac{T_b + T_c}{ T}$

=> $P(A) = \frac{ 206+ 182}{623}$

=>

So

$P(U |D ) = \frac{\frac{77}{ 623} }{ \frac{ 206+ 182}{623}}$

=> $P(U |D ) = 0.198$

Generally the probability that the death was from camping or being outside and was before 2001 is mathematically represented as

$P(O | B) = \frac{T_z}{ T}$

Here $T_z$ is the total number of death outside / camping before 2001 and the value is 117

So

$P(O \ n \ B) = \frac{117}{623}$

=> $P(O\ n \ B) = 0.188$

Generally the probability that the death was from camping or being outside given that it was before 2001 is mathematically represented as

$P(O | B) = \frac{ P( O \ n \ B)}{ P(B)}$

Here $P(B)$ is the probability that it was before 2001 , this is mathematically represented as

$P(B ) = \frac{T_a}{T}$

=> $P(B ) = \frac{235}{623}$

So

$P(O | B) = \frac{ \frac{117}{623}}{ \frac{235}{623}}$

=> $P(O | B) = 0.498$

5 0

2 years ago

hey i know this may be a lame question but can anyone help me how can i multiply 16 with 3,142 (with steps) ?? :/

vovangra [49]

Answer:

50272

Step-by-step explanation:

Okay how I solve these equations is I take the problem apart like this:

3142 = 3000 + 100 + 40 + 2

Now we multiply each number by 16:

3000 * 16 = 48000

100 * 16 = 1600

40 * 16 = 640

2 * 16 = 32

Then we add all the totals together:

48000 + 1600 + 640 + 32 = 50272

Hope this Helps ;)

8 0

2 years ago

Jamal hiked on two trails. The first trail was 7 1/3 miles long, and the second trail was 1 9/11 times as long as the first trai

algol [13]

9514 1404 393

Answer:

20 2/3 miles

Step-by-step explanation:

Altogether Jamal hiked 1 + 1 9/11 times the length of the first trail:

(2 9/11)(7 1/3) = (31/11)(22/3) = 62/3 = 20 2/3

Jamal hiked 20 2/3 miles.

7 0

2 years ago