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astraxan [27]
3 years ago
10

Is RATIONAL , IRRATIONAL,NON REAL NUMBERS

27" alt=" \sqrt{27" align="absmiddle" class="latex-formula">
​
Mathematics
2 answers:
Tanya [424]3 years ago
8 0

Answer:

It's irrational

Step-by-step explanation:

the square root of 27 is equal to:

\sqrt{27} = \sqrt{3\cdot3\cdot3} = 3\sqrt{3}

We know that \sqrt{3} is an irrational number (but a real number), so 3\sqrt{3} is the same.

In case we need to prove that \sqrt{3} is irrational, please leave a comment.

zepelin [54]3 years ago
8 0
The answer is Irrational
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<h3>Answer:   x = 6</h3>

======================================================

Work Shown:

\log_{4}(x+10)+\log_{4}(x-2)=\log_{4}(64)\\\\\log_{4}\left((x+10)(x-2)\right)=\log_{4}(64)\\\\(x+10)(x-2)=64\\\\x^2-2x+10x-20=64\\\\x^2-2x+10x-20-64=0\\\\

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