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astraxan [27]
3 years ago
10

Is RATIONAL , IRRATIONAL,NON REAL NUMBERS

27" alt=" \sqrt{27" align="absmiddle" class="latex-formula">
​
Mathematics
2 answers:
Tanya [424]3 years ago
8 0

Answer:

It's irrational

Step-by-step explanation:

the square root of 27 is equal to:

\sqrt{27} = \sqrt{3\cdot3\cdot3} = 3\sqrt{3}

We know that \sqrt{3} is an irrational number (but a real number), so 3\sqrt{3} is the same.

In case we need to prove that \sqrt{3} is irrational, please leave a comment.

zepelin [54]3 years ago
8 0
The answer is Irrational
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M is directly proportional to r2 <br> When r=2, m=14<br> Work out the value of m when r=12
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so M=(k)r^2

and when r=2, m=14

so 14=(k)(2)^2

k=14/4 =7/2

so when r=12

m= (7/2)(12)^2 =(7/2)(144) = 504

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Answer:

\boxed{\textsf {The value of c is $\sf \dfrac{-14}{3}$. }}

Step-by-step explanation:

A polynomial is given to us . We need to find the value of c so that it is divisible by (x-3 ) .The given polynomial to us is ,

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And the factor is ,

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