Answer: The percent yield is, 42%
Explanation:
To calculate the moles :
The balanced chemical reaction is:
According to stoichiometry :
1 moles of 
require = 3 moles of 
Thus 0.020 moles of will require=
of
Thus is the limiting reagent as it limits the formation of product and is the excess reagent.
As 1 mole of give = 2 moles of 
Thus 0.020 moles of give =
of
Theoretical mass of 
Actual mass of = 1.1 g
Now we have to calculate the percent yield
Therefore, the percent yield is, 42%
H-zone in a contracted sarcomere differ from that of a relaxed sarcomere . Yes its true because H-zone is narrower in contracted sarcomere. The functional unit of striated muscle is sarcomere. Sarcomere is the very basic unit of skelatal muscle. Between two Z line sarcomere is the repeated unit .Hence we can say that H-zone in a contracted sarcomere differ from that of a relaxed sarcomere.
True since some of the input energy is turned into heat energy, which is then lost in the environment. This is why input work is never equal to output work, unless the problem is set in a 'perfect world'.
Answer:
This is a poorly formatted question. B.
Explanation:
First of all, B is absolutely correct, but may not be within this context. I would answer B, but be ready to fight your teacher about it.
Answer:
B. It allows for genetic variation.
Explanation:
As prophase progresses, homologous chromosomes come to lie side by side and become intertwined rather like a zipper. This process is called synapsis. During synapsis, homologous chromosomes exchange genetic material between one another which allows for genetic variation. This exchange is called crossing over.
