All categories

2 years ago

Using the formula, find the slope of the line through the given points (9,7) and (7,9)

Mathematics

1 answer:

Nesterboy [21]2 years ago

7 0

Slope= y2-y1/x2-x1
so
slope=9-7/7-9
slope=-1

You might be interested in

The circle shown has a radius of 4 cm.

Vesna [10]

Answer:

8 cm

Step-by-step explanation:

4+4=8 To get the diameter, double the radius and add them together.

7 0

2 years ago

How do i solve this quadratic equation x²+6x+c

Anuta_ua [19.1K]

recall in a perfect square trinomial, the middle term is the tale-tell guy, we know the middle term is the product of 2 and the two other guys without the exponent, so in this case 6x = 2*√x² * √c.

$\bf 6x=2\cdot \sqrt{x^2}\cdot \sqrt{c}\implies 6x=2\sqrt{x^2c}\implies 6x=2x\sqrt{c}\\\\\\\cfrac{6x}{2x}=\sqrt{c}\implies 3=\sqrt{c}\implies 3^2=c\implies 9=c$

6 0

3 years ago

Graph the line with the equation y=1/3x+1

devlian [24]

Answer:

See photo

Step-by-step explanation:

$\frac{1}{3}$ = $\frac{rise}{run}$

1 = slope intercept

6 0

3 years ago

13. Maria earns $8 per hour plus a 5% commission on the price

Pani-rosa [81]

Answer:

Inequality:

120 + 0.05x ≥ 200

Solution:

x ≥ $1,600

Her total weekly sales must be equal to or greater than $1,600

Step-by-step explanation:

Let x represent the weekly sales she must make to reach her goal.

Given;

Pay rate = $8

Weekly total work hours = 15 hours

Commission on sales = 5% = 0.05

Total weekly earnings is;

8×15 + 0.05×x

120 + 0.05x

Minimum Weekly target earnings = $200

So;

120 + 0.05x ≥ 200

Solving the inequality equation;

0.05x ≥ 200 - 120

0.05x ≥ 80

x ≥ 80/0.05

x ≥ 1600

x ≥ $1,600

Her total weekly sales must be equal to or greater than $1,600

6 0

3 years ago

A truck can be rented from Company A for $70 a day plus $0.20 per mile. Company B charges $20 a day plus $0.40 per mile to r

Otrada [13]

Answer:

For Company A to have a better deal, the truck must be driven more than 250 miles per day.

Step-by-step explanation:

Given that:

Rent per day of company A = $70

Per mile charges = $0.20

Let,

x be the number of miles.

A(x) = 0.20x + 70

Rent per day of company B = $20

Per mile charges = $0.40

B(x) = 0.40x + 20

For make Company A better deal,

A(x) > B(x)

0.20x+70 > 0.40+20

0.20x-0.40x>20-70

-0.20x>-50

Dividing both sides by -0.20

$\frac{-0.20x}{-0.20}>\frac{-50}{-0.20}\\x>250$

Hence,

For Company A to have a better deal, the truck must be driven more than 250 miles per day.

8 0

3 years ago