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galben [10]
3 years ago
10

Harriet is helping her brother paint an art project like the one shown below. They plan to paint only the lateral faces. One qua

rt of paint covers 87 square feet.
If only full quarts can be
purchased, how many quarts of paint will they need to complete
the project if they plan on using one coat of paint?

Mathematics
1 answer:
Reil [10]3 years ago
8 0
I like cheese and cheese is good
You might be interested in
Easy points ^^
Shkiper50 [21]

Step-by-step explanation:

x = Alice's money

y = Mio's money

z = Grace's money

x + y + z = sum

there are originality 5+4+3 = 12 parts of the money shared between them.

x = 5/12 sum

y = 4/12 sum

z = 3/12 sum

after the money transfer we are only having 4+3+2 = 9 parts of the same money distributed.

so, we are dealing with 1/9 parts.

let's bring everything to 1/36 to be able to truly compare things.

therefore

x = 15/36 sum

y = 12/36 sum

z = 9/36 sum

15/36 sum + 10 = 16/36 sum

because 4/9 = 16/36

10 = 1/36 sum

sum = 10×36 = £360

so, together they have £360.

and they had before the £10 transfer £150, £120, £90.

after the £10 transfer they had £160, £120, £80.

5 0
3 years ago
Alice purchased 4 1⁄2 kilograms of olive oil for $27. What is the price per kilogram
Bas_tet [7]
Do 27 divided by 4 1/2 or 4.5. That will be your answer. Let me know if this helps!
5 0
3 years ago
Read 2 more answers
An item has a listed price of $75. If the sales tax rate is 3%, how much is the sales tax (in dollars)?
Daniel [21]

Answer:

Net Price: $ 75.00

+ Sales Tax (3%): $ 2.25

Total Price: $ 77.25

5 0
3 years ago
Find the perimeter and area
vesna_86 [32]
The answer for this problem is 1893 Cm squared.
8 0
3 years ago
19) A submarine ascended from 56.8 meters under the sea level to 27.4 meters under the sea level.
ElenaW [278]

Answer:

29.4 meters

Step-by-step explanation:

Given the following :

A submarine ascended from 56.8 meters under the sea level to 27.4 meters under the sea level.

distance it moved between two positions. Use the "distance on the number line "formula

Initial Position or distance of submarine before ascension = 56.8 meters

Final position after ascension = 27.4 meters

The distance moved by the submarine between the two positions can be obtained by.

(Initial distance - Final distance)

(56.8 - 27.4) = 29.4 meters

5 0
3 years ago
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