d. y = 3/4x + 17/4.
To write the slope-intercept form y = mx + b of a line passing through (-3, 2) and (1,5).
First, we have to calculate the slope m.
m = (y₂-y₁)/(x₂-x₁), with (x₁, y₁) = (-3, 2) and (x₂, y₂) = (1, 5)
m = (5 - 2)/(1 - (-3))
m = 3/4
Second, we have to find the y-intercept.
y = mx + b, where m is the slope and b is the y-intercept.
Using one of the two ordered pair and plug it in for x and y in the equation y = mx + b.
Taking the ordered pair (1, 5):
5 = 3/4 (1) + b
5 = 3/4 + b
Solving for b
b = 5 - 3/4
b = [5(4) - 3(1)]/4
b = (20 - 3)/4
b = 17/4
Finally, write down the slope-intercept equation of the form y = mx + b, with m = 3/4 and b = 17/4:
y = mx + b
y = 3/4x + 17/4
Answer:
b. cosine t less than 0 and cotangent t greater than 0
Step-by-step explanation:
We have the following relation
if we apply the cosine function in the relation we get:
the cosine of t is between 0 and -1 then (cosine t less than 0)
If we now apply cotangent function in the relation:
This means that cotang is greater than 0, therefore the correct answer is b. cosine t less than 0 and cotangent t greater than 0
Answer:
97 minutes
Step-by-step explanation:
There are 60 minutes in an hour.
60+37=97
====50 do you need the exaple or no.====
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<span>Wanda started walking along a path 27 seconds before Dave. Wanda walked at a constant rate of 3 feet per second. Dave walked along the same path at a constant rate of 4.5 feet per second. How long after Dave starts walking will he catch up with Wanda ?
***
let x=travel time of Dave
x+27=travel time of Wanda
speed*travel time=distance (same for both Wanda and dave)
..
4.5x=3(x+27)
4.5x=3x+81
1.5x=81
x=54
How long after Dave starts walking will he catch up with Wanda ? 54 sec</span>
