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3 years ago

A set of input and output values, such that each input has one or more outputs, is called a

Mathematics

1 answer:

Ainat [17]3 years ago

5 0

Answer:

function

Step-by-step explanation: A function is the one where you put an input to find x or y

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5. Find the thickness of each layer. Use the data to determine the percentage of the total

zmey [24]

Answer:

Exosphere - 10,000 kilometers thick

Thermosphere - 513 kilometers

Mesosphere - 2200 km

Stratosphere - Depends, but most occurring thickness is 50km

Troposphere - 8-14km

Step-by-step explanation:

Double check and verify this information with your lesson since honestly the numbers could very well differ depending on your lesson and when they were taken. I hope this helps though..have a good one

3 0

2 years ago

4(-2d-3)=12, someone please solve this for me asap

wlad13 [49]

4(-3 + -2d) = 12

(-3 * 4 + -2d * 4) = 12

(-12 + -8d) = 12

-12 + -8d = 12

-12 + 12 + -8d = 12 + 12

-12 + 12 = 0

0 + -8d = 12 + 12

-8d = 12 + 12

12 + 12 = 24

-8d = 24

d = -3

5 0

3 years ago

-8x-11x what is the answer

gregori [183]

Answer:

-19x

Step-by-step explanation:

so you start with -8 and when you subtract 11 from -8 its the same as adding them but because your subtracting you'll decrease which make the answer -19x. (hopefully this made sense)

7 0

2 years ago

Easy variable question pls help

svet-max [94.6K]

Answer:

z = -4 1/2

Step-by-step explanation:

1. First change the mixed fractions to improper fractions so it's easier

$\frac{16}{5\\}/(z-\frac{1}{2}) = \frac{8}{3}/(z+\frac{1}{3})$

2. Simplify

$\frac{32}{5(2z-1)} = \frac{8}{3z+1}$

3. Cross multiply

$32(3z+1) = 5(2z-1) * 8$

4. Simplify again (distributive property)

$32(3z+1) = 40(2z-1)$

5. Distributive property

$32(3z+1) -> 96z+32$

$40(2z-1) -> 80z-40$

$96z+32=80z-40$

6. Subtract 32 from both sides

$96z+32-32 = 80z-40-32$

7. Simplify

$96z = 80z-72$

8. Subtract 80 from both sides

$96z-80z=80z-72-80z$

9. Simplify

$16z=-72$

10. Divide both sides by 16

$\frac{16z}{16}=\frac{-72}{16}$

11. Simplify

$z=-\frac{9}{2} -> also = -4\frac{1}{2}$

Sorry if it was too long but hope this helps! :)

And also try using symbolab cuz it gives step by step explanations it's really good!

7 0

2 years ago

If f and g are differentiable functions for all real values of x such that f(1) = 4, g(1) = 3, f '(3) = −5, f '(1) = −4, g '(1)

belka [17]

Answer:

h'(1)=0

Step-by-step explanation:

We use the definition of the derivative of a quotient:

If $h(x)=\frac{f(x)}{g(x)}$ , then:

$h'(x)=\frac{f'(x)*g(x)-f(x)*g'(x)}{(g(x))^2}$

Since in our case we want the derivative of $h(x)$ at the point x = 1, which is indicated by: h'(1), we need to evaluate the previous expression at x = 1, that is:

$h'(1)=\frac{f'(1)*g(1)-f(1)*g'(1)}{(g(1))^2}$

which, by replacing with the given numerical values:

$f(1) =4\\g(1)=3\\f'(1)=-4\\g'(1)=-3$

becomes:

$h'(1)=\frac{f'(1)*g(1)-f(1)*g'(1)}{(g(1))^2}=\\=\frac{-4*3-4*(-3)}{(3)^2}=\frac{-12+12}{9} =\frac{0}{9} =0$

3 0

3 years ago