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3 years ago

10

Jess wrote Amanda a check for $358.36, and Amanda deposited the check into her checking account. Where was Amanda's signature? A

. On both the front of the check and the back of the check B. Only on the front of the check C. On neither the front of the check nor the back of the check D. Only on the back of the check

2 answers:

Alex777 [14]3 years ago

6 0

The answer is "A" because the one on the front is to let the bank teller that it is to you and the one on the back is let them know that it is really you

Alex17521 [72]3 years ago

4 0

Answer:

Only on the back of the check

APEX

Step-by-step explanation:

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Help pls!<br> simplify<br> -6 x^{2} ÷ 12 - 2(-7)<br><br> a. -17<br> b. 35<br> c. -35<br> d. 11

Mariana [72]

Answer:

11

Step-by-step explanation:

Given: $\frac{-6^{2}}{12} -2(-7)$

Using PEDMAS rule to solve it.

Now, simplifying:

We first open parenthesis which is (-7) = -7

= $\frac{-6^2}{12}-2\times -7$

Now, we evaluate the exponent which is $-6^2=-36$

Next, we divide -36 by 12 to get -3

= $\frac{-36}{12}-2\times -7 \\= -3 -2\times -7$

Next, we multiply -2 and -7 to get 14

= $-3 + 14$

Lastly, we add -3 and 14 to get 11

= $11$

∴ Answer is 11

5 0

3 years ago

Weekly wages at a certain factory are

lesantik [10]

The answer should be 2.35

7 0

3 years ago

Part 2: Create a scenario for a geometric sequence. For example, Anthony goes to the gym for ______ minutes on Monday. Every day

Ugo [173]

An example scenario is:

Anthony goes to the gym for <em>20</em> minutes on Monday. Every day he <em>multiplies</em> his gym time by <em>2</em>.

On the fifth day, he will spend spend 320 minutes in the gym.

The formula used to determine the 5th term is,

a5 = 20 x 2^(r -1)

where r is the common ratio equal to 2.

5 0

3 years ago

Several factors influence the size of the F-ratio. For each of the following, indicate whether it would influence the numerator

enyata [817]

Answer:

(a) Increase the differences between the sample means this will increase the Numerator.

(b) Increase the sample variances will increase the denominator.

Step-by-step explanation:

F Ratio = Variance between treatments/ Variance within treatments.

Here,

(a) Increase the differences between the sample means:

- Will increase the Numerator and

- Size of the F-ratio would increase

(b) Increase the sample variances:

- Will increase the denominator and

- Size of the F Ratio would decrease.

8 0

3 years ago

A circle is translated 4 units to the right and then reflected over the x-axis. Complete the statement so that it will always be

irga5000 [103]

Answer:

The statement is now presented as:

$\exists\, (h,k)\in \mathbb{R}^{2} /f: (x-h^{2})+(y-k)^{2}=r^{2}\implies f': [x-(h+4)]^{2}+[y-(-k)]^{2} = r^{2}$

In other words, this mathematical statement can be translated as:

<em>There is a point (h, k) in the set of real ordered pairs so that a circumference centered at (h,k) and with a radius r implies a equivalent circumference centered at (h+4,-k) and with a radius r. </em>

Step-by-step explanation:

Let $C = (h,k)$ the coordinates of the center of the circle, which must be transformed into $C'=(h', k')$ by operations of translation and reflection. From Analytical Geometry we understand that circles are represented by the following equation:

$(x-h)^{2}+(y-k)^{2} = r^{2}$

Where $r$ is the radius of the circle, which remains unchanged in every operation.

Now we proceed to describe the series of operations:

1) <em>Center of the circle is translated 4 units to the right</em> (+x direction):

$C''(x,y) = C(x, y) + U(x,y)$ (Eq. 1)

Where $U(x,y)$ is the translation vector, dimensionless.

If we know that $C(x, y) = (h,k)$ and $U(x,y) = (4, 0)$ , then:

$C''(x,y) = (h,k)+(4,0)$

$C''(x,y) =(h+4,k)$

2) <em>Reflection over the x-axis</em>:

$C'(x,y) = O(x,y) - [C''(x,y)-O(x,y)]$ (Eq. 2)

Where $O(x,y)$ is the reflection point, dimensionless.

If we know that $O(x,y) = (h+4,0)$ and $C''(x,y) =(h+4,k)$ , the new point is:

$C'(x,y) = (h+4,0)-[(h+4,k)-(h+4,0)]$

$C'(x,y) = (h+4, 0)-(0,k)$

$C'(x,y) = (h+4, -k)$

And thus, $h' = h+4$ and $k' = -k$ . The statement is now presented as:

$\exists\, (h,k)\in \mathbb{R}^{2} /f: (x-h^{2})+(y-k)^{2}=r^{2}\implies f': [x-(h+4)]^{2}+[y-(-k)]^{2} = r^{2}$

In other words, this mathematical statement can be translated as:

<em>There is a point (h, k) in the set of real ordered pairs so that a circumference centered at (h,k) and with a radius r implies a equivalent circumference centered at (h+4,-k) and with a radius r. </em>

<em />

4 0

3 years ago