3/4 times 5=
5 times 3=15
15/4=3 3/4
3 3/4 is answer
Given, To make a strawberry shortcake for one person, we need :
▪︎
cup of strawberry
▪︎one shortbread biscuit
Quantity of strawberries Elisa has = 3 cups
Number of shortbread biscuits she has = 12
Number of shortcakes she can make :



Thus, Elisa can serve strawberry shortcakes to 9 people.
With 12 dozen shortbread biscuits she can serve 12 people.
Quantity of strawberries needed to serve 12 people :



<h3>○=> Therefore :</h3>
▪︎Elisa can serve strawberry shortcakes to <u>9 people</u>.
▪︎Elisa will need <u>4 cups of strawberries</u> if she wants to use all dozen shortbread biscuits.
Answer:B
Step-by-step explanation:
If d=4 and Danny has 7 more peices all you have to do is multiply. 7x4 and that equals 28
So the final answer is 28 which is choice B
Answer:
y = -2x +6
second equation is incorrect.
because there are 2 equal signs in that equation
Step-by-step explanation:
Answer:
0.0228 = 2.28% probability that a randomly selected firm will earn more than Arc did last year
Step-by-step explanation:
Normal Probability Distribution:
Problems of normal distributions can be solved using the z-score formula.
In a set with mean
and standard deviation
, the z-score of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.
Suppose the mean income of firms in the same industry as Arc for a year is 45 million dollars with a standard deviation of 7 million dollars
This means that 
What is the probability that a randomly selected firm will earn more than Arc did last year?
Arc earned 59 million, so this is 1 subtracted by the pvalue of Z when X = 59.



has a pvalue of 0.9772
1 - 0.9772 = 0.0228
0.0228 = 2.28% probability that a randomly selected firm will earn more than Arc did last year