All categories

2 years ago

How can you put -4/5 on the number line

Mathematics

2 answers:

MArishka [77]2 years ago

8 0

Draw a number line. Make sure that the values -1 and 0 are on it. In between these two values, cut the interval into 5 equal slices. It doesn't have to be perfect. Just the general idea is what counts. Place your pencil at 0 and then count four spots to the left until you arrive at -4/5

See the attached image for visual details.

Sindrei [870]2 years ago

5 0

divide the space between one and zero into five and put it on the section closest to one but not on it

You might be interested in

a toy store marks down every toy by 15% in January. How much does a toy cost during January? Use p for the price in December.

satela [25.4K]

A toy cost 0.85p in January.

Step-by-step explanation:

Given,

Mark down in January = 15%

Let,

Price in December = p

Mark down in January = 15% of price in December

Mark down in January = $\frac{15}{100}*p$

Mark down in January = 0.15p

Price of toy in January = Price in December - Mark down

Price of toy in January = p - 0.15p = 0.85p

A toy cost 0.85p in January.

Keywords: mark down, subtraction

Learn more about subtraction at:

#LearnwithBrainly

7 0

3 years ago

HELLLLLLLLPPPPPPP MEEEEE!!!!

Sergio [31]

Ali's solution is incorrect
same as 9y + 1y
10y

6 0

3 years ago

How many distinct rearrangements of the letters in "tweedledee" are there?

podryga [215]

Answer:

weed ,led ,we, tee , tweedle

4 0

2 years ago

Need help ASAP <br><br> HELP PLEASEE

Leokris [45]

A. Categorical
b. I think walking group (I’m not sure)
c. Bar graph

6 0

2 years ago

Solve 2cos ²y -siny -1=0 for 0° ≤y≤360°

natima [27]

$\displaystyle\bf\\2cos^2y -sin\,y -1=0~~~for~~0^o\leq y \leq360^o\\\\cos^2y=1-sin^2y\\\\2(1-sin^2y) -sin\,y -1=0\\\\2-2sin^2y-sin\,y-1=0\\\\-2sin^2y-sin\,y+2-1=0\\\\-2sin^2y-sin\,y+1=0~~~\Big|\times(-1)\\\\2sin^2y+sin\,y-1=0$

$\displaystyle\bf\\\boxed{\bf sin\,y=x}\\\\2x^2+x-1=0\\\\x_{12}=\frac{-b\pm\sqrt{b^2-4ac}}{2a}=\frac{-1\pm\sqrt{1-4\cdot2\cdot(-1)}}{2\cdot2}=\\\\=\frac{-1\pm\sqrt{1+8}}{4}=\frac{-1\pm\sqrt{9}}{4}=\frac{-1\pm3}{4}\\\\x_1=\frac{-1+3}{4}=\frac{2}{4}=\boxed{\bf\frac{1}{2}}\\\\x_2=\frac{-1-3}{4}=\frac{-4}{4}=\boxed{\bf-1}\\\\sin\,y=\frac{1}{2}\\\\\boxed{\bf y_1=\frac{\pi}{6}~~or~~(30^o)}\\\\\boxed{\bf y_2=\frac{5\pi}{6}~~or~~(150^o)}\\\\sin\,y=-1\\\\\boxed{\bf y_3=\frac{3\pi}{2}~~or~~(270^o)}$

5 0

2 years ago