Answer:
Yes
Step-by-step explanation:
Answer:
The answer to the question is
It take for the golf ball hit on Mars to reach the ground 8.284 s longer.
Step-by-step explanation:
To Solve the question, we note that the equation of motion is given to us as
h = -1.9·t² + 26·t
Therefore the height
We compare the above equation with the equation of of motion
S = ut - 0.5×g×t² where u = initial velocity = 26 m/s and - 0.5×g = -1.9
Therefore the acceleration due to gravity om mars = -1.9/-0.5 = 3.8 m/s²
We now have the time taken to maximum height given by
v = u - g·t where v = 0 at maximum height
We therefore have u = g·t → 26 = 3.8×t or t = 26/3.8 = 6.84 seconds
The time taken for ball to hit the ground is 2 × the time to reach maximum height = 2 × 6.84 = 13.684 s
The time longer it takes for the ball on Mars to complete the path up to maximum height and down again is 13.684 s - 5.4 s = 8.284 s.
If it’s under 90 make a acute angle of it 90 make a right angle if it’s over 90 make a obtuse angle
Answer:
A = (2x² + 4x + 1) (8 − x)
A = -2x³ + 12x² + 31x + 8
Step-by-step explanation:
W = 2x² + 4x + 1
L = 8 − x
Area is width times length.
A = (2x² + 4x + 1) (8 − x)
If you wish, you can simplify with distribution.
A = 8 (2x² + 4x + 1) − x (2x² + 4x + 1)
A = 16x² + 32x + 8 − 2x³ − 4x² − x
A = -2x³ + 12x² + 31x + 8
