Ansa million. once you're staring at in ordinary terms one technology, it relatively is, all those fruit flies have been produced via 2 mum and dad, then the only plausible parental genotype that provide you a 50/50 ratio is that if the mummy is XwXw and the father is Xry... this gene is carried on the X chromosome, and w represents white eyes and r represents purple eyes. you are able to bypass forward and draw this out in case you like, even yet it provides 50% heterozygous women individuals (with purple eyes, provided that purple is dominant), and 50% white eyed men, who can in ordinary terms inherit Xw from their mom. The Y that they could inherit from the father could have not any effect on their eye shade. it relatively is comparable for women individuals, they are in a position to in ordinary terms inherit Xw from their mom and an Xr from their father, meaning they'll continually be heterozygous for the attention shade gene. 2. returned, set us the genotypes so which you will visualize it; we are going to say that this disease is carried on the X chrmsm (thats whats usually assumed), and the gene for customary creative and prescient is XB, yet for colorblindness its Xb. those are dominant/recessive to boot. So, if the girl is a provider, her genotype is XBXb, and if the male is colorblind, his genotype is XbY. in case you draw this out in a punett sq., you will get 25% heterozygous woman, 25% colorblind woman, 25% well-known male, and 25% colorblind male. so, there's a 50% risk that any baby they have would be colorblind, 50% risk if its a woman, or 50% risk if it relatively is male.wer:
Explanation:
The question is incomplete. The complete question is as follows:
Which of the following mutations is most likely to cause a phenotypic change?
A) a duplication of all or most introns
B) a large inversion whose ends are each in intergenic regions
C) a nucleotide substitution in an exon coding for a transmembrane domain
D) a single nucleotide deletion in an exon coding for an active site
E) a frameshift mutation one codon away from the 3' end of the nontemplate strand
Answer: D) a single nucleotide deletion in an exon coding for an active site
Explanation:
Deletion or insertion of a single nucleotide in an axon coding for an active site is called frameshift mutation.
The sequence of codons is read during translation, in order to synthesize a amino acids chain and form a protein from the nucleotide sequence. Frameshift mutations occur when the usual codon sequence is broken by the deletion or addition of one or more nucleotides. For example, if only one nucleotide is removed from the axon sequence during the RNA splicing process, then there will be a disrupted reading frame for all codons before and after the mutation. This may result in several incorrect amino acids being introduced into the protein. Disruption in protein sequence will cause phenotypic change.
Hence, the correct option is D) a single nucleotide deletion in an exon coding for an active site
.
I think the correct stage would be In the prophase.
Has a cell wall but lacks a well-defined nucleus and organelles, and its cytoplasm doesn't have much structure.
is to manage the blood circulation to the heart muscle. The Left main
coronary artery (LMCA) distributes blood to the left side of your heart
muscle and the Right coronary artery (RCA) distributes blood to the right
atrium, right ventricle, sinoatrial (SA) and atrioventicular (AV) nodes, which
controls your heart rhythm.
