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Doss [256]
3 years ago
13

7(8 + y) simplified?

Mathematics
1 answer:
Juli2301 [7.4K]3 years ago
3 0

Factor out the equation

(7 x 8) + (7 x Y)

56 + 7y

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The corresponding ordered pairs are (0,4) (1,3) (2,2) and ( 4,0)
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Jhon went to the cinema to watch a film at quarter past 3. The film lasted for an hour, What time did he leave?
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Help please! Identify an equation in point slope form for the line perpendicular to Y =-4x + 8 that passes through (-2, 7)
777dan777 [17]

Answer:

D. y-7=\frac{1}{4}(x+2)

Step-by-step explanation:

The point-slope form of a line is given by:

y-y_1=m(x-x_1)

The line given to us has equation; y=-4x+8.

The slope of this line is -4. The of the line perpendicular to this line is the negative reciprocal of the slope of the given line.

Our slope of interest is therefore; m=\frac{1}{4}

Since the point goes through (-2,7), we have x_1=-2,y_1=7.

We plug in the slope and the point into the point-slope formula to obain;

y-7=\frac{1}{4}(x--2)

The required equation is:

y-7=\frac{1}{4}(x+2)

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6 0
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Read 2 more answers
ASAP! triangle ACD is an isosceles triangle. the height is 12. the base is 10. Round your angle measures to the nearest tenth. F
hammer [34]

Answer:

Part 1) The length of DC is 13\ units

Part 2) The measures of the angles in the isosceles triangle are

The base angles are 67.4° and the vertex angle is 45.2°

Step-by-step explanation:

step 1

In the right triangle BDC Find the length of DC

Applying the Pythagoras Theorem

DC^{2}=BC^{2} +BD^{2}

we have

BC=AB=10/2=5\ units

BD=12\ units

substitute

DC^{2}=5^{2} +12^{2}

DC^{2}=169

DC=13\ units

step 2

Find the measures of internal angles in the isosceles triangle ABC

we know that

∠DAC=∠DCA ------> base angles

∠ADC ------> vertex angle

<em>Find the measure of angle DCA</em>

In the right triangle BDC

sin(∠DCA)=BD/DC

substitute the values

sin(∠DCA)=12/13

∠DCA=arcsin(12/13)=67.4°

so

∠DAC=∠DCA=67.4°

<em>Find the measure of angle ∠ADC</em>

Remember that the sum of the internal angles of a triangle must be equal to 180 degrees

so

∠DAC+∠DCA+∠ADC=180°

substitute

67.4°+67.4°+∠ADC=180°

∠ADC=180°-134.8°=45.2°

3 0
3 years ago
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