The period is equal to 2pi/n, where n is the coefficient of t. In this case pi/2. Therefore the period in this example is 4. Frequency is equal to 1/period. Hence the frequency for this problem is 1/4
We need to figure out how much string would be left, after taking away the first two pieces.
We know that the first piece is 20 inches long, so we can say that there is 52-20 inches left, or 32 inches.
The second piece is between 12 and 18 inches, meaning that there would be between 32-12 and 32-18 inches left for the third piece, or 20 and 14 inches. This means that the third piece would be at least 14 inches long, but no more than 20, since we don’t have more string than that (20+12+20=52, and 20+14+18=52)
So we can say that x is greater or equal to 14, but less than or equal to 20, or:
14<=x<=20 (“<=“ is written like a normal “<“ sign with a line _ right under it)
Answer:
210
Step-by-step explanation:
because you use 13.% divided by the price
Original position:
A-(-8,-4)
B-(-6,3)
C-(-3,7)
D-(-2,-2)
Translation:
A'-(-4,-4)
B'-(-2,3)
C'-(1,7)
D'-(2,-2)
Vertex C will be in quadrant 1 (+,+) after being translated 4 unites to the right.
24 x 8 = 192
192 / 2 = 96
I am not sure if my answer is true.
