If the gum costs 75 cents today, which is 3 cents less than three times what the pack cost 20 years ago, we just need to arrange what we know into an equation.
We know that the price of gum today is 75 cents, so we can leave that on one side of the equation as a constant. Also, since we are dealing only with cents and not dollars, there is no need to shift the decimal point to the left.
? = 75
Now, we can work the equation.
The problem tells us that 75 is 3 cents less than three times the old cost. So, if x is the old cost, we can work out the equation based on that.
It says that it's 3 cents less than 3 times x. The question is basically the equation in word form.
3x - 3 = 75
'3x' being the "three times the old cost" part, '- 3' being the "3 cents less" part, and '75' of course being the current price of a pack of gum.
Option C is your correct answer.
BTW if we were to solve this, we would see that the old price of a pack of gum is:
3x - 3 = 75
+ 3 + 3
3x = 78
/3 /3
x = 26
20 years ago, a 75-cent pack of gum cost 26 cents.
Hope that helped! =)
Answer: your answer should be HI i hope it helps
Multiply first equation by 8,
24x + 40y = 352
Multiply second equation by 3,
24x - 21y = -75
Now, subtract second from 1st,
61y = 427
y = 427/61
y = 7
Substitute it in very first equation,
3x + 5(7) = 44
3x = 44 - 35
x = 9 / 3
x =3
In short, Your Answer would be Option D) (3, 7)
Hope this helps!
Answer:
hope this helps
Step-by-step explanation:
Step 1: Enter an algebraic expression in the input field Step 2: Now click the button “Submit” to get the equivalent expression Step 3: Finally, the equivalent expression for the given algebraic expression will be displayed in a new window. What is an Algebraic Expression? An algebraic expression is an expression which consists of variables, coefficients, constants, and mathematical operators such as addition, subtraction, multiplication, and division.
The number of miles in a day at which the rental costs for Company A and Company B are the same is 140 miles
<h3>Rental cost</h3>
Let
Company A:
90 + 0.20x
Company B:
20 + 0.70x
90 + 0.20x = 20 + 0.70x
90 - 20 = 0.70x - 0.20x
70 = 0.50x
- Divide both sides by 0.50
x = 70/0.50
x = 140 miles
Therefore, the number of miles in a day at which the rental costs for Company A and Company B are the same is 140 miles
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