2 years ago

Find the distance (-1,-2) and (3,-1)

Mathematics

1 answer:

jasenka [17]2 years ago

5 0

Answer:

$\sqrt{17}$

Step-by-step explanation:

$\sqrt{4^2 + 1^2}$

$\sqrt{17}$

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The simplified expression of $(4^3)(\frac{4^4^0x^4}{3^2x^2y^2})$ is $\frac{4^7x^2}{3^2y^2}$

<h3>How to simplify the expression?</h3>

The expression is given as:

$(4^3)(\frac{4^4^0x^4}{3^2x^2y^2})$

Expressions raise to power 0 is 1.

So, we have:

$(4^3)(\frac{4^4x^4}{3^2x^2y^2})$

Apply the law of indices to expression with common base

$(\frac{4^{4+3}x^{4-2}}{3^2y^2})$

Evaluate the sum and difference

$(\frac{4^7x^2}{3^2y^2})$

Remove the bracket

$\frac{4^7x^2}{3^2y^2}$

Hence, the simplified expression of $(4^3)(\frac{4^4^0x^4}{3^2x^2y^2})$ is $\frac{4^7x^2}{3^2y^2}$