All categories

3 years ago

What is the image of (9,0) after a dilation by a scale factor of 2 centered at the origin?

Mathematics

1 answer:

Advocard [28]3 years ago

6 0

(5,7). Because the origin centers 2 by dilation.

You might be interested in

Solve both by substitution method (algebra 2) and show work please<br><br> -2x-7y=22<br>-7x-5y=-1

Alex17521 [72]

$\bf \begin{cases}
-2x-7y=22\\
-7x-5y=-1
\end{cases}\qquad \textit{let's solve the \underline{second one} for "x"}
\\\\\\
-7x-5y=-1\implies -7x=5y-1\implies x=\cfrac{5y-1}{-7}
\\\\\\
\boxed{x=\cfrac{1-5y}{7}}\impliedby \textit{now, let's substitute it in the \underline{first one}}
\\\\\\$

$\bf -2\left( \frac{1-5y}{7} \right)-7y=22\implies \cfrac{10y-2}{7}-7y=22
\\\\\\
\textit{now, let's multiply both sides by 7, to toss the denominator}
\\\\\\
7\left( \cfrac{10y-2}{7}-7y \right)=7(22)\implies 10y-2-49y=154
\\\\\\
-39y=156\implies y=\cfrac{154}{-39}\implies \boxed{y=-4}
\\\\\\
\textit{now, let's use that in the \underline{first one}}
\\\\\\
-2x-7(-4)=22\implies -2x+28=22\implies 6=2x\implies \cfrac{6}{2}=x
\\\\\\
\boxed{3=x}$

4 0

3 years ago

Please give an explanation thank youuu<br> Write √216 as a power of 6

Nesterboy [21]

Answer:

solution

here,

<h3>the power of route 216 of 6 is 6to the power 3</h3>

3 0

2 years ago

Read 2 more answers

Suppose you were adding 527+405. What would the tens problem be

nydimaria [60]

it would be 3 because when you add it, it gets to be 932 and the tens place is 3.

8 0

3 years ago

Do the following side lengths form a triangle?<br><br> 6, 18, 14

iren2701 [21]

Answer:

Yes

Step-by-step explanation:

Conditions for the sides to form a triangle is that sum of any two sides should be greater than the third side.

6 + 18 = 24

24 > 14

18 + 14 = 32

32 > 6

6 + 14 = 20

20 > 18

Therefore,

sides 6, 18 and 14 forms a triangle.

5 0

3 years ago

Amanda created a table to help her represent the sample space of spinning a spinner and flipping a coin.

OlgaM077 [116]

Answer:

$\sf \dfrac{1}{8}$

Step-by-step explanation:

Spinner choices: Red, Green, Yellow, Blue

Coin choices: Heads, Tails

$\large\begin{array}{| c | c | c | c | c |}\cline{1-5} & \sf Red & \sf Green & \sf Yellow & \sf Blue\\\cline{1-5} \sf Heads & RH & GH &YH & BH \\\cline{1-5} \sf Tails &RT & GT& YT& BT\\\cline{1-5}\end{array}$

$\sf Probability\:of\:an\:event\:occurring = \dfrac{Number\:of\:ways\:it\:can\:occur}{Total\:number\:of\:possible\:outcomes}$

$\implies \sf P(blue)=\dfrac{1}{4}$

$\implies \sf P(heads)=\dfrac{1}{2}$

$\implies \sf P(blue)\:and\:P(heads)=\dfrac{1}{4} \times \dfrac{1}{2}=\dfrac{1}{8}$

5 0

2 years ago