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inysia [295]
3 years ago
5

Help me ASAP this is important

Mathematics
1 answer:
Valentin [98]3 years ago
3 0
The second option the height is 18 .
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Find the x-intercept and the y-intercept of the graph of the equation 11x+12y=8
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The answer would be (8/11,0) as the x-intercept
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Simplify the expression (62)4.
BARSIC [14]

Answer:

(31)2 is the answer to (62)4

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
Please help fast......
Tom [10]

3)

\begin{array}{c|c}\underline{Statement}&\underline{Reason}\\ 1.AY=BX&\text{1. Given}\\ 2.AB \cong AB&\text{2. Reflexive Property}\\ 3. AD || BC&\text{3. Property of a square}\\ 4. \angle ABE \cong \angle AXB&\text{4. Alternate Interior Angles}\\ 5. \angle BAY \cong \angle BYA&\text{5. Alternate Interior Angles}\\6. \triangle BAX \cong \triangle ABY&\text{6. Angle-Side-Angle Theorem}\\ 7. AX \cong BY&\text{7. CPCTC}\\\end{array}

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\begin{array}{c|c}\underline{Statement}&\underline{Reason}\\1. AB=CF&\text{1. Given}\\2.AB+BF=A'F&\text{2. Segment Addition Postulate}\\3.CF+BF=A'F&\text{3. Substitution Property}\\4.CF+BF+BC&\text{4. Segment Addition Postulate}\\5.A'F=BC&\text{5. Transitive Property}\\6. \angle AFE = \angle DBC&\text{6. Given}\\7. EF = BD&\text{7. Given}\\8. \triangle AFE \cong \triangle CBD&\text{8. Side-Angle-Side Theorem}\\\end{array}

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7)

\begin{array}{c|c}\underline{Statement}&\underline{Reason}\\\text{1.AC bisects }\angle BAD&\text{1. Given}\\2. \angle BAC \cong \angle DAC&\text{2. Property of angle bisector}\\3.AC = AC&\text{3. Reflexive Property}&4. \angle ACB \cong \angle ACD&\text{4. Property of angle bisector}\\5. \triangle ABC \cong \triangle ADC&\text{5. Angle-Side-Angle Theorem}\\6.BC=CD&\text{6. CPCTC}\\\end{array}

5 0
3 years ago
What does sin^2 x - cos^2 x equal
Stels [109]

Answer:

-cos(2x)

Step-by-step explanation:

I did trig last year and tutor a trig class this year :)

6 0
2 years ago
Suppose an=3an-1 -5an-2 -4an-3. and a4= -7, a5=-36, a6=-85 , find a1 , a2, a3​
maria [59]

Answer:

        a_1=4\\\\a_2=0\\\\a_3=3

Explanation:

The equation is:

      a_n=3a_{n-1}-5a_{n-2}-4a_{n-3}

and

      a_4=-7, a_5=-36, a_6=-85

<u>1. Subsittute n = 6 into the equation:</u>

      a_6=3a_{5}-5a_{4}-4a_{3}

      Now subsititute the known values:

       -85=3(-36)-5(-7)-4a_{3}

      You can solve for a_3

      -85=-108+35-4a_{3}\\\\4a_3=12\\\\a_3=12/4\\\\a_3=3

<u />

<u>2. Substitute n = 5 into the equation:</u>

    a_5=3a_{4}-5a_{3}-4a_{2}

     Substitute the known values and solve for a_2

        -36=3(-7)-5(3)-4a_{2}\\\\4a_2=-21-15+36=0\\\\a_2=0

<u>3. Substitute n = 4 into the equation, subsitute the known values and solve for </u>a_1<u />

       a_4=3a_{3}-5a_{2}-4a_{1}

        -7=3(3)-5(0)-4a_{1}\\\\4a_1=9+7=16\\\\a_1=4

7 0
3 years ago
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