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deff fn [24]
2 years ago
14

Christina is packing different books into boxes. The paperback books weigh 0.8 pounds each. The hardcover books weigh 1.3 pounds

each. Christina needs to pack the boxes so that there are at least 20 books in each box, but the boxes cannot weigh more than 30 pounds. Identify Christina's set of constraints. Check all that apply.

Mathematics
1 answer:
IgorC [24]2 years ago
8 0

Answer:

x\geq0, y\geq0, x+y\geq20, and 8x+13y\leq300.

Step-by-step explanation:

Let x and y be the numbers of the paperback book and the hardcover book respectively.

as x and y are the counting numbers, so it will be always positive. So,

x\geq0\;\dots(i) and

y\geq0\;\cdots(ii)

Given that the weight of 1 paperback book=0.8 pounds and

the weight of 1 paperback book=1.3 pounds.

There are at least 20 books in each box, so

x+y\geq20\;\cdots(iii)

As one box cannot weigh more than 30 pounds, so

0.8x+1.3y\leq30

\Rightarrow 8x+13y\leq300\;\cdots(iv)

Now, from the equations (i),(ii),(iii), and (iv), all the sets of constraints as

x\geq0, y\geq0, x+y\geq20, and 8x+13y\leq300.

Moreover, the sets of all the integral values of (x,y) in the shaded region are the feasible numbers of the paperback book and hardcover book.

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3 years ago
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The combination shows that the numbers of possible live card hands drawn without replacement from a standard deck of 52 playing cards is 2,598,960.

<h3>How to explain the information?</h3>

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In the last quarter of​ 2007, a group of 64 mutual funds had a mean return of 2.2 2.2​% with a standard deviation of 6.3 6.3​%.
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Answer:

a) 0.625; b) 16.879; c) 8.442

Step-by-step explanation:

Since this is a normal distribution, we want the value of the mean, μ:  2.2; and the value of the standard deviation, σ:  6.3.

For the 40th percentile, we look in a z chart.  We want to find the value as close to 0.40 as we can get; this is 0.4013, and it corresponds to a z score of z = -0.25.

Our formula for a z score is z=\frac{X-\mu}{\sigma}.  Using our values, we have

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For the 99th percentile, the value in the z chart closest to 0.99 is 0.9901, which corresponds to a z score of z = 2.33:

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Add 2.2 to each side:

14.679+2.2 = X-2.2+2.2

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For the IQR, we find the values for the 75th percentile (Q3) and the 25th percentile (Q1).  The value in a z chart closest to 0.75 is 0.7486, which corresponds to a z score of z = 0.67:

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Multiply both sides by 6.3:

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Add 2.2 to each side:

4.221+2.2 = X-2.2+2.2

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The value in a z chart closest to 0.25 is 0.2514, which corresponds to a z score of z = -0.67:

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Multiply both sides by 6.3:

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-4.221 = X-2.2

Add 2.2 to each side:

-4.221+2.2 = X-2.2+2.2

-2.021 = X

This makes the interquartile range

6.421--2.021 = 8.442

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