Question

The time in seconds, t, it takes for a specific object being dropped from a particular height in feet above sea level, h, to reach the ground can be found by the radical function t equals one fourth times radical h period At what height should you drop an object in order for it to reach the ground in 8 seconds?
1,024 feet
256 feet
64 feet
4 feet

Answer 1

Applying the function, it is found that the object was dropped from a height of 256 feet.

--------------------

The time it takes for the object to hit the ground is given by:

$t(h) = \sqrt{\frac{h}{4}}$

--------------------

• It took 8 seconds to hit the ground, thus, $t = 8$, and we have to solve for the height h.

$t(h) = \sqrt{\frac{h}{4}}$

$8 = \sqrt{\frac{h}{4}}$

$(\sqrt{\frac{h}{4}})^2 = 8^2$

$\frac{h}{4} = 64$

$h = 4(64) = 256$

The object was dropped from a height of 256 feet.

A similar problem is given at brainly.com/question/22277316