$w-width\\2w-1-length\\w(2w-1)=2w^2-w-the\ area\\28\ ft^2-the\ area\\\\\text{The equation:}\\\\2w^2-w=28\qquad\text{subtract 28 from both sides}\\\\2w^2-w-28=0\\\\2w^2-8w+7w-28=0\\\\2w(w-4)+7(w-4)=0\\\\(w-4)(2w+7)=0\iff w-4=0\ \vee\ 2w+7=0\\\\w-4=0\qquad\text{add 4 to both sides}\\\boxed{w=4}\\\\2w+7=0\qquad\text{subtract 7 from both sides}\\2w=-7\qquad\text{divide both sides by 2}\\w=-3.5$

7 0

3 years ago

Read 2 more answers

Help please

Mademuasel [1]

If Triangle ABC is similar to triangle DEF, then ∠A is congruent to ∠D, ∠B is congruent to ∠E, and ∠C is congruent to ∠F.

If ∠E = 40°, then ∠B = 40°.

There are 180° in a triangle. If ∠A = 35° and ∠B = 40°, then ∠C = 180° - 35° - 40°.

180 - 35 - 40 = 105°
m∠C = 105°

8 0

2 years ago

Need of helpp for my test

katrin [286]

Answer:

-2

Step-by-step explanation:

5 0

3 years ago

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Sorry forgot to post the problem here it is

vovikov84 [41]

Answer:

Step-by-step explanation:

m angle A and m angle C are equal sine two of those sides are equal. You would do 3x + 40 = x +50

You subtract x, leaving it to be 2x + 40 = 50

Subtract the 40, leaving it be 2x = 10

Divide both sides by 2, which leaves x = 5

and then you would do 3(5) + 40, which is 55

4 0

2 years ago